Python练习题答案: 删除第一次和最后一个字符【难度：0级】--景越Python编程实例训练营,1000道上机题等你来挑战

删除第一次和最后一个字符【难度:0级】:

答案1:

def remove_char(s):
    return s[1 : -1]​

答案2:

def remove_char(s):
    #your code here
    return s[1:-1]​

答案3:

def remove_char(s):
    #your code here
    return(s[1:-1])​

答案4:

def remove_char(s):
    return s[1:-1]
    #your code here​

答案5:

def remove_char(s):
    return s[1:-1];​

答案6:

def remove_char(s):
    return (s[1:-1])​

答案7:

def remove_char(s):
    return (s)[1:-1]​

答案8:

def remove_char(s):
    return (s[1:-1])#your code here​

答案9:

In[14]: def remove_char(s):
   ...:     return s[1:-1]
   ...: 
   ...: 
   ...: def remove_char_2(s):
   ...:     s = list(s)
   ...:     s.pop()
   ...:     s.pop(0)
   ...:     return ''.join(s)
   ...: 
In[15]: %timeit remove_char('abcdefg')
The slowest run took 15.26 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 328 ns per loop
In[16]: %timeit remove_char_2('abcdefg')
The slowest run took 7.71 times longer than the fastest. This could mean that an intermediate result is being cached.
100000 loops, best of 3: 2.23 µs per loop

​

答案10:

def remove_char(s):
    return '' if len(s) <= 2 else s[1:-1]​

答案11:

def remove_char(s):
    return s[1:len(s)-1]​

答案12:

def remove_char(s):
    #your code here
   return s[1:len(s)-1]​

答案13:

def remove_char(s):
    #your code here
    return s[1:(len(s) -1)]​

答案14:

def remove_char(s):
    return (s[1:(len(s)-1)])​

答案15:

def remove_char(s):
    return s[1:len(s) - 1]
    #your code here​

答案16:

def remove_char(s):
   return (s[1:len(s)-1])​

答案17:

def remove_char(s):
    return s[1:(len(s)-1)]​

答案18:

def remove_char(s):
    return s[1:(len(s)-1)]#your code here​

答案19:

def remove_char(s):
    return s[1:len(s) - 1];
    #your code here​

答案20:

def remove_char(s):
    return(s[1:len(s)-1])
    #your code here​

答案21:

def remove_char(s):
    return s[1:((len(s))-1)]​

答案22:

def remove_char(s):
    return(s)[1:(len(s)-1)]​

答案23:

def remove_char(s):
    #your code here
    return(s[1:len(s)-1])​

答案24:

def remove_char(s):
    #your code here
  return s[1:len(s)-1];​

答案25:

def remove_char(s):
    return(s[1:(len(s)-1)])
    #your code here​

答案26:

def remove_char(s):
    return s[1:(len(s))-1]​

答案27:

def remove_char(s):
    return s[1:len(s)-1];​

答案28:

def remove_char(s):
    return(s[1:len(s)-1]);
    ​

答案29:

def remove_char(s):
    return((s[1:(len(s)-1)]))​

答案30:

def remove_char(s):
    #your code here
    return s[1:((len(s))-1)]​

答案31:

def remove_char(s):
    #your code here
    return s[1:(len(s))-1]​

答案32:

def remove_char(s):
    s = list(s)
    s.pop()
    s.pop(0)
    return ''.join(s)​

答案33:

def remove_char(s):
    s = list(s)
    s.pop()
    s.pop(0)
    return "".join(s)​

答案34:

def remove_char(s):
    if s == "eloquent":         #confirming the s variable equals the word "eloquent"
        return(s[1:7])          #telling the program if s is "eloquent" print all except first and last letters
    elif s == "country":        #confirming the s variable equals the word "country"
        return(s[1:6])          #telling the program if s is "country" print all except first and last                             
    elif s == "person":         #same as 1,3
        return(s[1:5])          #same as 2,4
    elif s == "place":          #same as 1,3
        return(s[1:4])          #same as 2,4
    elif s == "ok":             #same as 1,3
        return""                #telling the program if s is "ok" don't print anything, ok is only 2 letters
    else:                       #if anything else is entered,
        return(s[1:-1])         #tell the program s is the input without the first and last characters​

答案35:

def remove_char(s):
    #your code here
    if s is not None and len(s) > 1:
        return s[1:len(s)-1]
    
    return s​

答案36:

def remove_char(s):
    if len(s)>0:
       return s[1:-1]
    else:
       return ''​

答案37:

def remove_char(s):
    #your code here
    if len(s) > 2:
        x = s[1:-1]
        return x
    else:
        return ''​

答案38:

def remove_char(s):
    #your code here
    s = s[1:-1]
    return s​

答案39:

def remove_char(s):
    s = s[1:-1]
    return s​

答案40:

def remove_char(s):
    s = s[1:-1]
    return(s)​

答案41:

def remove_char(s):
    #your code here
    s = s[1:-1]
    return(s)​

答案42:

def remove_char(s):
    s = s[1:-1]
    return s
    #your code here​

答案43:

def remove_char(s):s = s[1:-1];return s​

答案44:

def remove_char(s):
    s = (s[1:-1])
    return s​

答案45:

def remove_char(s):
    s = s[1:-1]
    return s;​

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