欧拉法、预估校正法(改进的欧拉法)与四阶龙格库塔法求解常微分方程的数值解C++程序

以y'=x+y,0<x<1,y(0)=1为例，取步长h=0.1，已知精确值为y=-x-1+2e^x，用来进行精度比较

#include<stdio.h>
using namespace std;
double cor[10000];
double f(double x,double y)//改写函数
{
    return x+y;
}
double correctf(double x)//精确解函数
{
    return -x-1+2*exp(x);
}
void Euler(double h,double l,double r,double *a,double *b,double tol)//欧拉法
{
    double sum=0;
    for(int i=1; i<=tol; i++)
    {
        b[i]=b[i-1]+h*f(a[i-1],b[i-1]);
        sum+=fabs(b[i]-cor[i])/cor[i];
    }
    for(int i=1; i<=tol; i++)
        printf("当x=%lf时，近似解为:%lf，准确解为:%lf\n",a[i],b[i],cor[i]);
    printf("精度为:%lf\n\n",sum/tol);
}
void improvedEuler(double h,double l,double r,double *a,double *b,double tol)//改进的欧拉法
{
    double b1,sum=0;
    for(int i=1; i<=tol; i++)
    {
        b1=b[i-1]+h*f(a[i-1],b[i-1]);
        b[i]=b[i-1]+h/2*(f(a[i-1],b[i-1])+f(a[i],b1));
    }
    for(int i=1; i<=tol; i++)
        printf("当x=%lf时，近似解为:%lf，准确解为:%lf\n",a[i],b[i],cor[i]);
    printf("精度为:%lf\n\n",sum/tol);
}
void RungeKutta(double h,double l,double r,double *a,double *b,double tol)//四阶龙格库塔法
{
    double k1,k2,k3,k4,sum=0;
    for(int i=1; i<=tol; i++)
    {
        k1=f(a[i-1],b[i-1]);
        k2=f(a[i-1]+h/2,b[i-1]+h/2*k1);
        k3=f(a[i-1]+h/2,b[i-1]+h/2*k2);
        k4=f(a[i-1]+h,b[i-1]+h*k3);
        b[i]=b[i-1]+h/6*(k1+2*k2+2*k3+k4);
    }
    for(int i=1; i<=tol; i++)
        printf("当x=%lf时，近似解为:%lf，准确解为:%lf\n",a[i],b[i],cor[i]);
    printf("精度为:%lf\n\n",sum/tol);
}
int main()
{
    double h,a[10000],b[10000],l,r;
    memset(a,0,sizeof(a));
    memset(b,0,sizeof(b));
    memset(cor,0,sizeof(cor));
    printf("请输入步长:");
    scanf("%lf",&h);
    printf("请输入区间下限:");
    scanf("%lf",&l);
    printf("请输入区间上限:");
    scanf("%lf",&r);
    printf("请赋予初始值:");
    scanf("%lf",&b[0]);
    double tol=(r-l)/h;
    for(int i=0; i<=tol; i++)
        a[i]=l+i*h;
    for(int i=1; i<=tol; i++)
        cor[i]=correctf(a[i]);
    printf("以下为欧拉法求解结果:\n");
    Euler(h,l,r,a,b,tol);
    printf("以下为改进的欧拉法求解结果:\n");
    improvedEuler(h,l,r,a,b,tol);
    printf("以下为四阶龙格库塔法求解结果:\n");
    RungeKutta(h,l,r,a,b,tol);
    return 0;
}