java Servlet之HttpServlet
程序员文章站
2024-02-28 12:06:52
...
1、web.xml文件（放在WEB-INF文件下）指定访问类的路径
- servlet和servlet-mapping通过servlet-name连接在一起
- url-parttern为在浏览器*问的路径，前面记得要加/
<servlet>
<servlet-name>EServlet</servlet-name>
<servlet-class>cn.itcast.web.servlet.EServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>EServlet</servlet-name>
<url-pattern>/EServlet</url-pattern>
</servlet-mapping>
2、EServlet类（例子）
package cn.itcast.web.servlet;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class EServlet extends HttpServlet {
//HttpServlet虽然是抽象类 但没有任何抽象方法
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
System.out.println("dopost()...");
}
}
3、html文件（WebRoot文件夹下）
<!DOCTYPE html>
<html>
<head>
<title>login.html</title>
<meta name="keywords" content="keyword1,keyword2,keyword3">
<meta name="description" content="this is my page">
<meta name="content-type" content="text/html; charset=UTF-8">
<!--<link rel="stylesheet" type="text/css" href="./styles.css">-->
</head>
<body>
This is my HTML page. <br>
<form action="/day09_1/EServlet" method="post">//这里方法定义为post，动作指向EServlet类
<input type="submit" value="点击提交"/>
</form>
</body>
</html>
4、结果:EServlet类没有重写doGet方法 所以显示405错误
（只重写了doPost方法，只支持post方法）