基于Struts文件上传(FormFile)详解

<form action="/strutsfileupanddown/register.do" method="post" enctype="multipart/form-data">
 名字：<input type="text" name="name" />
 头像:<input type="file" name="file"/>
 <input type="submit" value="注册用户">
 </form>

/*
 * generated by myeclipse struts
 * template path: templates/java/javaclass.vtl
 */
package com.yourcompany.struts.form;
 
import javax.servlet.http.httpservletrequest;
import org.apache.struts.action.actionform;
import org.apache.struts.action.actionmapping;
import org.apache.struts.upload.formfile;
 
/**
 * myeclipse struts
 * creation date: 08-24-2017
 *
 * xdoclet definition:
 * @struts.form name="userform"
 */
public class userform extends actionform {
 /*
  * generated methods
  */
 
 private string username;
 private formfile file;
  
 public string getusername() {
  return username;
 }
 public void setusername(string username) {
  this.username = username;
 }
 public formfile getfile() {
  return file;
 }
 public void setfile(formfile file) {
  this.file = file;
 }
 
}

userform userform = (userform) form;
string username = userform.getusername();
formfile file = userform.getfile();
 
//通过formfile可以获取关于用户上传文件的各种信息
//用于获取文件名字
string filename = file.getfilename();
//用于获取文件大小
int filesize = file.getfilesize();

try {
 //获取输入流
 is = file.getinputstream();
 
 //得到输出流
 //1.得到file文件夹，上传到tomcat服务器后的绝对路径(file文件为新创建的文件夹）
 string filepath = this.getservlet().getservletcontext().getrealpath("/file");
 //两个"//"的其中一个"/"为转义符
  os=new fileoutputstream(filepath+"\\"+filename);
  
 int len=0;//表示读取的字节
 //做一个缓存，防止文件过大而造成错误
 byte[] buff=new byte[1024];
 while((len=is.read(buff))!=-1)
 {
  os.write(buff,0,len);
 }
 is.close();
 os.close();
}