Android字符串和十六进制相互转化出现的中文乱码问题

废话不读说了，直接给大家贴代码了，代码附有注释，可以说明一切，本文写的不好，还请见谅。

import java.io.bytearrayoutputstream;
/**
* created by administrator on 2016/2/2.
* -----------16进制和字符串互转---------
* ------------解决中文乱码问题---------
*/
public class stringtosixthutils {
private static string hexstring = "0123456789abcdef";
/*
* 将字符串编码成16进制数字,适用于所有字符（包括中文）
*/
public static string encode(string str) {
//根据默认编码获取字节数组
byte[] bytes = str.getbytes();
stringbuilder sb = new stringbuilder(bytes.length * 2);
//将字节数组中每个字节拆解成2位16进制整数
for (int i = 0; i < bytes.length; i++) {
sb.append(hexstring.charat((bytes[i] & 0xf0) >> 4));
sb.append(hexstring.charat((bytes[i] & 0x0f)));
}
return sb.tostring();
}
/*
* 将16进制数字解码成字符串,适用于所有字符（包括中文）
*/
public static string decode(string bytes) {
bytearrayoutputstream baos = new bytearrayoutputstream(bytes.length() / 2);
//将每2位16进制整数组装成一个字节
for (int i = 0; i < bytes.length(); i += 2)
baos.write((hexstring.indexof(bytes.charat(i)) << 4 | hexstring.indexof(bytes.charat(i + 1))));
return new string(baos.tobytearray());
}
}

下面给大家分享一段代码关于16进制字符串和字节数组互相转换

package com.wpn.net.util; 
public class numberchange { 
/* 
* 把16进制字符串转换成字节数组 @param hex @return 
*/ 
public static byte[] hexstringtobyte(string hex) { 
int len = (hex.length() / 2); 
byte[] result = new byte[len]; 
char[] achar = hex.tochararray(); 
for (int i = 0; i < len; i++) { 
int pos = i * 2; 
result[i] = (byte) (tobyte(achar[pos]) << 4 | tobyte(achar[pos + 1])); 
} 
return result; 
} 
private static byte tobyte(char c) { 
byte b = (byte) "0123456789abcdef".indexof(c); 
return b; 
} 
/** 
* 把字节数组转换成16进制字符串 
* 
* @param barray 
* @return 
*/ 
public static final string bytestohexstring(byte[] barray) { 
stringbuffer sb = new stringbuffer(barray.length); 
string stemp; 
for (int i = 0; i < barray.length; i++) { 
stemp = integer.tohexstring(0xff & barray[i]); 
if (stemp.length() < 2) 
sb.append(0); 
sb.append(stemp.touppercase()); 
} 
return sb.tostring(); 
} 
/** 
* @函数功能: bcd码转为10进制串(阿拉伯数据) 
* @输入参数: bcd码 
* @输出结果: 10进制串 
*/ 
public static string bcd2str(byte[] bytes) { 
stringbuffer temp = new stringbuffer(bytes.length * 2); 
for (int i = 0; i < bytes.length; i++) { 
temp.append((byte) ((bytes[i] & 0xf0) >>> 4)); 
temp.append((byte) (bytes[i] & 0x0f)); 
} 
return temp.tostring().substring(0, 1).equalsignorecase("0") ? temp.tostring().substring(1) : temp.tostring(); 
} 
/** 
* @函数功能: 10进制串转为bcd码 
* @输入参数: 10进制串 
* @输出结果: bcd码 
*/ 
public static byte[] str2bcd(string asc) { 
int len = asc.length(); 
int mod = len % 2; 
if (mod != 0) { 
asc = "0" + asc; 
len = asc.length(); 
} 
byte abt[] = new byte[len]; 
if (len >= 2) { 
len = len / 2; 
} 
byte bbt[] = new byte[len]; 
abt = asc.getbytes(); 
int j, k; 
for (int p = 0; p < asc.length() / 2; p++) { 
if ((abt[2 * p] >= '0') && (abt[2 * p] <= '9')) { 
j = abt[2 * p] - '0'; 
} else if ((abt[2 * p] >= 'a') && (abt[2 * p] <= 'z')) { 
j = abt[2 * p] - 'a' + 0x0a; 
} else { 
j = abt[2 * p] - 'a' + 0x0a; 
} 
if ((abt[2 * p + 1] >= '0') && (abt[2 * p + 1] <= '9')) { 
k = abt[2 * p + 1] - '0'; 
} else if ((abt[2 * p + 1] >= 'a') && (abt[2 * p + 1] <= 'z')) { 
k = abt[2 * p + 1] - 'a' + 0x0a; 
} else { 
k = abt[2 * p + 1] - 'a' + 0x0a; 
} 
int a = (j << 4) + k; 
byte b = (byte) a; 
bbt[p] = b; 
} 
return bbt; 
} 
public static void main(string[] arg) { 
/** 
* 68 65 6c 6c 6 f 0a 
* c4 e3 ba c3 
*/ 
string[] str = {"c4", "e3", "ba", "c3"}; 
// string[] str = {"7e","02","04","00","07","10","00","00","00","00","13","08","4f","01","0b","0b","15","10","14","13","44","7e"}; 
byte[] b = new byte[str.length]; 
for(int i=0;i<str.length;i++){ 
b[i] = hexstringtobyte(str[i])[0]; 
} 
system.out.println(new string(b)); 
string strc ="你好"; 
string bth=bytestohexstring(strc.getbytes()); 
system.out.println(bth); 
system.out.println(short.max_value); 
system.out.println(integer.tobinarystring(280)); 
} 
}

以上所述是本文给大家分享的android字符串和十六进制相互转化出现的中文乱码问题的相关内容，希望对大家有所帮助。