js中怎么获取url后面的多个参数

例如 :url路径如下

url:  http://localhost:8080/Demo/Demo.jsp?userid=001

js代码获取url中"?"符后的字串（参数）：

var url = document.location.href;   // 获取url完整路径    
var theRequest = {};
  if (url.indexOf("?") != -1) {
	   var str = url.substr(url.indexOf("?")+1);  // str = "userid=001"
	   strs = str.split("&");  
	   for(var i = 0; i < strs.length; i ++) {
	        var st = strs[i].split("=");    //str = (2) ["userid","001"]
	        if(st.length > 1)
	             theRequest[st[0]] = st[1];  // theRequest = {userid : "001"}
	   }
  }
  this.user = theRequest.userid;   // 此时 this.user的值为001
	```