js/jquery 获取url传递参数，js获取url？号后面的参数（一个或多个）

第一种方法：
（获取一个）
detail.html?order_id=10

<Script language="javascript">  
    function GetRequest() {  
       var url = location.search; //获取url中"?"符后的字串  
       var theRequest = new Object();  
       if (url.indexOf("?") != -1) {  
          var str = url.substr(1);  
          strs = str.split("&");  
          for(var i = 0; i < strs.length; i ++) {  
             theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);  
          }  
       }  
       return theRequest;  
    }  
    </script> 

调取

$(document).ready(function(){
    var a=GetRequest();
    var order_id = a['order_id'];
    // console.log(order_id)
	Detail(order_id);
     })

获取两个的（仔细看差别）
detail.html?order_id=10?uid=3

function GetRequest() {
    var url = location.search; //获取url中"?"符后的字串
    var theRequest = new Object();
     if (url.indexOf("?") != -1) {
           var str = url.substr(1);
           strs = str.split("?");
           console.log(strs)
           for (var i = 0; i < strs.length; i++) {
               theRequest[strs[i].split("=")[0]] = decodeURIComponent(strs[i].split("=")[1]);
           }
       }
       return theRequest;
    }

调用

$(document).ready(function(){
    var a=GetRequest();
    var order_id = a['order_id'];
    var uid = a['uid'];  
    // console.log(order_id)
    //console.log(uid)
    Detail(order_id,uid);
 })

其他方法参见下面这篇博客
https://www.cnblogs.com/karila/p/5991340.html