Mysql select in 按id排序实现方法
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2024-02-16 14:50:04
表结构如下: mysql> select * from test; +----+-------+ | id | name | +----+-------+ | 1 |...
表结构如下:
mysql> select * from test;
+----+-------+
| id | name |
+----+-------+
| 1 | test1 |
| 2 | test2 |
| 3 | test3 |
| 4 | test4 |
| 5 | test5 |
+----+-------+
执行以下sql:
mysql> select * from test where id in(3,1,5);
+----+-------+
| id | name |
+----+-------+
| 1 | test1 |
| 3 | test3 |
| 5 | test5 |
+----+-------+
3 rows in set (0.00 sec)
这个select在mysql中得结果会自动按照id升序排列,
但是我想执行"select * from test where id in(3,1,5);"的结果按照in中得条件排序,即:3,1,5,
想得到的结果如下:
id name
3 test3
1 test1
5 test5
请问在这样的sql在mysql中怎么写?
网上查到sqlserver中可以用order by charindex解决,但是没看到mysql怎么解决??请高手帮忙,谢
谢!
select * from a order by substring_index('3,1,2',id,1);
试下这个good,ls正解。
order by find_in_set(id,'3,1,5')
谢谢,经测试order by substring_index和order by find_in_set都可以
mysql> select * from test;
+----+-------+
| id | name |
+----+-------+
| 1 | test1 |
| 2 | test2 |
| 3 | test3 |
| 4 | test4 |
| 5 | test5 |
+----+-------+
执行以下sql:
mysql> select * from test where id in(3,1,5);
+----+-------+
| id | name |
+----+-------+
| 1 | test1 |
| 3 | test3 |
| 5 | test5 |
+----+-------+
3 rows in set (0.00 sec)
这个select在mysql中得结果会自动按照id升序排列,
但是我想执行"select * from test where id in(3,1,5);"的结果按照in中得条件排序,即:3,1,5,
想得到的结果如下:
id name
3 test3
1 test1
5 test5
请问在这样的sql在mysql中怎么写?
网上查到sqlserver中可以用order by charindex解决,但是没看到mysql怎么解决??请高手帮忙,谢
谢!
select * from a order by substring_index('3,1,2',id,1);
试下这个good,ls正解。
order by find_in_set(id,'3,1,5')
谢谢,经测试order by substring_index和order by find_in_set都可以