欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页

android uri 解析获取文件真实路径(兼容7.0+)

程序员文章站 2024-02-13 23:17:34
...

主要是兼容7.0以后的fileProvider 把URI 以content provider 方式 对外提供的解析方法

   public static File getFileFromUri(Uri uri, Context context) {
        if (uri == null) {
            return null;
        }
        switch (uri.getScheme()) {
            case "content":
                return getFileFromContentUri(uri, context);
            case "file":
                return new File(uri.getPath());
            default:
                return null;
        }
    }
    /**
     * Gets the corresponding path to a file from the given content:// URI
     *
     * @param contentUri The content:// URI to find the file path from
     * @param context    Context
     * @return the file path as a string
     */

    private static File getFileFromContentUri(Uri contentUri, Context context) {
        if (contentUri == null) {
            return null;
        }
        File file = null;
        String filePath;
        String fileName;
        String[] filePathColumn = {MediaStore.MediaColumns.DATA, MediaStore.MediaColumns.DISPLAY_NAME};
        ContentResolver contentResolver = context.getContentResolver();
        Cursor cursor = contentResolver.query(contentUri, filePathColumn, null,
                null, null);
        if (cursor != null) {
            cursor.moveToFirst();
            filePath = cursor.getString(cursor.getColumnIndex(filePathColumn[0]));
            fileName = cursor.getString(cursor.getColumnIndex(filePathColumn[1]));
            cursor.close();
            if (!TextUtils.isEmpty(filePath)) {
                file = new File(filePath);
            }
            if (!file.exists() || file.length() <= 0 || TextUtils.isEmpty(filePath)) {
                filePath = getPathFromInputStreamUri(context, contentUri, fileName);
            }
            if (!TextUtils.isEmpty(filePath)) {
                file = new File(filePath);
            }
        }
        return file;
    }
    /**
     * 用流拷贝文件一份到自己APP目录下
     *
     * @param context
     * @param uri
     * @param fileName
     * @return
     */
    public static String getPathFromInputStreamUri(Context context, Uri uri, String fileName) {
        InputStream inputStream = null;
        String filePath = null;

        if (uri.getAuthority() != null) {
            try {
                inputStream = context.getContentResolver().openInputStream(uri);
                File file = createTemporalFileFrom(context, inputStream, fileName);
                filePath = file.getPath();

            } catch (Exception e) {
                L.e(e);
            } finally {
                try {
                    if (inputStream != null) {
                        inputStream.close();
                    }
                } catch (Exception e) {
                    L.e(e);
                }
            }
        }

        return filePath;
    }

    private static File createTemporalFileFrom(Context context, InputStream inputStream, String fileName)
            throws IOException {
        File targetFile = null;

        if (inputStream != null) {
            int read;
            byte[] buffer = new byte[8 * 1024];
            //自己定义拷贝文件路径
            targetFile = new File(getCacheDir(context), fileName);
            if (targetFile.exists()) {
                targetFile.delete();
            }
            OutputStream outputStream = new FileOutputStream(targetFile);

            while ((read = inputStream.read(buffer)) != -1) {
                outputStream.write(buffer, 0, read);
            }
            outputStream.flush();

            try {
                outputStream.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

        return targetFile;
    }

因为有拷贝文件和读取文件操作,所以在6.0以上需要申请权限