PHP事务的如何写?

PHP 的事务怎么写? 我现在是一条update,一条insert
代码如下,错误是,值类型发生了错误,事务没起作用.

$db = new DbManager();	$conn = $db->getConnection();	$conn->set_charset("utf8");		if(mysqli_connect_errno())	{		echo 'error connect database! please content manager!';		exit;	}	//echo connection_status();	$tbNums = explode(',',$tbNum);		$conn->autocommit(FALSE);	$flag = true;	$a=0;	foreach($tbNums as $key => $value)	{		$updateBalance = "UPDATE T_SMS_TBNUM SET STATUS = 2 WHERE ID = ?";		$insertRelate = "INSERT INTO T_SMS_TBNUMRELATE (TBID,OWNCLIENTID,REALFEE,CREATETIME) VALUES(?,?,?,?)";						$stmtUpdateClient = $conn->prepare($updateBalance);		$stmtUpdateClient->bind_param('i',$value);		$ss = $stmtUpdateClient->execute();				$stmt = $conn->prepare($insertRelate);		$foura = 4;		$a++;		if($a!=0){			$value = 's';		}		$stmt->bind_param('iids',$value,$clientId,$foura,date('Y-m-d H:i:s'));		$boooo = $stmt->execute();		echo $ss.'+'.$boooo;		if($stmtUpdateClient->affected_rows affected_rows affected_rows.'|'.$stmt->affected_rows;			$flag = false;			break;		}	}		if(!$flag)		{			$conn ->rollback();			$conn -> autocommit(TRUE);			$conn->close();			return 'paylog false!';		}else		{			$conn->commit();			$conn -> autocommit(TRUE);			$conn->close();			return '1';		}

回复讨论(解决方案)

if( $stmt->affected_rows affected_rows rollback();					$conn -> autocommit(TRUE);					$conn->close();			return 'unknow_error';		}else		{					$conn->commit();					$conn -> autocommit(TRUE);					$conn->close();			return '1';		}