还是关于PHP的二进制流问题

之前发了一帖: http://bbs.csdn.net/topics/391024843
版主给了回答,也能够解析出来,但却发现出来的结果与真实结果完全不一样,比如服务器返回给我的是: ip: 107.145.107.140, port: 26773
但我解析出来却变成了: ip: 46.48.46.48, port: 63271
这样就差的远了, 我用PHP去获取nodes信息,然后将nodes信息自己解析输出一遍,顺便把未解析数据发送给pthon解析一遍,然后两边对比,发现结果却不一样

PHP(使用了swoole):

set(array(    'worker_num' => WORKER_NUM,    'daemonize' => false,    'max_request' => MAX_REQUEST,    'dispatch_mode' => 2,    'debug_mode' => 1));$serv->on('Start', function($serv){    echo "DHT Server start...\n";    $nid = get_node_id();    $msg = array(        't' => entropy(2),        'y' => 'q',        'q' => 'find_node',        'a' => array(            'id' => $nid,            'target' => $nid        )    );    $serv->sendto(gethostbyname('router.bittorrent.com'), 6881, encode($msg));});$serv->on('Receive', function($serv, $fd, $from_id, $data){    echo "New receive from ip: ";    $msg = decode($data);    $fdinfo = $serv->connection_info($fd);    echo $fdinfo['remote_ip'] . "\n";    if($msg['y'] == 'r'){        if(array_key_exists('nodes', $msg['r']))            //$this->response_actions($msg, array($fdinfo['remote_ip'], $fdinfo['remote_port']));            $nodes = decode_nodes($msg['r']['nodes']);            foreach($nodes as $node){                echo "nid: " . $node->nid . ", ip: " . $node->ip . ", port: " . $node->port . "\n";            }            $serv->sendto('127.0.0.1', 6813, $data);    }});function entropy($length=20){        $s = '';        for($i=0;$istart();

python:

#!/usr/bin/env python#encoding: utf-8import socketfrom hashlib import sha1from random import randintfrom struct import unpackfrom socket import inet_ntoafrom threading import Timer, Threadfrom time import sleepfrom collections import dequefrom bencode import bencode, bdecodedef decode_nodes(nodes):    n = []    length = len(nodes)    if(length % 26) != 0:        return n    for i in range(0, length, 26):        nid = nodes[i:i+20]        ip = inet_ntoa(nodes[i+20:i+24])        ip2 = nodes[i+20:i+24]        print ip2        port = unpack("!H", nodes[i+24:i+26])[0]        port2 = nodes[i+24:i+26]        print port2        print "decode_nodes: nid: %s, ip: %s, port: %s\n" % (nid, ip, port)class DHTServer():    def __init__(self):        self.ufd = socket.socket(socket.AF_INET, socket.SOCK_DGRAM, socket.IPPROTO_UDP)        self.ufd.bind(("0.0.0.0", 6813))    def process_find_node_response(self, msg, address):        nodes = decode_nodes(msg["r"]["nodes"])        for node in nodes:            (nid, ip, port) = node            print "find_node: nid: %s, ip: %s, port: %s\n" % (nid, ip, port)    def run(self):        while True:            try:                (data, address) = self.ufd.recvfrom(65536)                msg = bdecode(data)                self.on_message(msg, address)            except Exception:                pass    def on_message(self, msg, address):        try:            if msg["y"] == "r":                if msg["r"].has_key("nodes"):                    self.process_find_node_response(msg, address)        except KeyError:            passif __name__ == "__main__":    # max_node_qsize bigger, bandwith bigger, spped higher    dht = DHTServer()    dht.run()

回复讨论(解决方案)

你把执行 decode_nodes($msg) 时的 $msg 用
echo base64_encode($msg);
输出出来看看

这个不是base64编码,而是类似于:
未编码: {"t":"aa", "y":"r", "r":{"id":"0123456789abcdefghij", "nodes":"def456..."}}
编码后:d1:rd2:id20:0123456789abcdefghij5:nodes9:def456...e1:t2:aa1:y1:re
这样的格式

而其中的nodeid、ip、port就是其中的nodes里的

你把执行 decode_nodes($msg) 时的 $msg 用
echo base64_encode($msg);
输出出来看看

这里有份DHT协议说明: http://blog.csdn.net/xxxxxx91116/article/details/7970815

我又不做这个，没兴趣看协议文本

我给你的解码格式是小端序的，如果你的数据是大端序的，那么就查一下 pack 函数说明，换一下

如果你想让我帮你检查，那么就请按我说的去做

4楼版主说的对，检查大小端序的问题。
或者用tcpdump实际的二进制数据是什么样的。

现在已经能够正确获取IP地址，但是端口依然无解，也的确是使用大端序，但PHP只有这几种格式，每个都试过，就是不正确，郁闷了。。。

那有什么办法呢？让你贴出数据你又不肯，只能这样了

啊，没有不肯啊，是这样的：
比如服务器发了一段数据过来，ip是：188.19.238.146，端口是：6881，然后我截取端口位的2字节数据为：?
接着就是解码，将网络字节序转换为端口号：unpack("n", $port)，但是转换出来却变成了57763，用unpack("s", $port)变成了-23583，用unpack("S", $port)变成了41953

让你把你收到的数据用 base64_encode 编码后给我，怎么就那么难呢？

让你把你收到的数据用 base64_encode 编码后给我，怎么就那么难呢？

抱歉，是这样的数据：

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

python 中有

    n = []    length = len(nodes)    if(length % 26) != 0:        return n

而你给的数据（解码后）长度是 474
模 26 为 6
请确认你给的数据是正确的

python 中有

    n = []    length = len(nodes)    if(length % 26) != 0:        return n

而你给的数据（解码后）长度是 474
模 26 为 6
请确认你给的数据是正确的

哦，抱歉，是这样的，刚才给出的是获取到的原始数据，而之后那里 % 26那个是通过bencode解码后的nodes数据，不好意思，忘了把这份数据也弄出来。。。

这份是原始数据，包含了获取到的所有，比如：y = r 之类的

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

这份是通过bencode解码后的nodes数据，也就是在这个数据中分成每份26字节，从26字节中取出20字节的nid，4字节的ip，2字节的端口：

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

$s = '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';$s = base64_decode($s);foreach(str_split($s, 26) as $s) {  $r = unpack('a20n/Nip/np', $s);  $r['ip'] = long2ip($r['ip']);  print_r($r);}

Array(    [n] => ?ÒÈõF E?(õRq)îȦG?4    [ip] => 78.235.194.139    [p] => 30295)Array(    [n] => ?ÒÈõF E?(õRq)îȦG?4    [ip] => 78.235.194.139    [p] => 30295)Array(    [n] => ?ÒÈõF E?(õRq)îȦG?4    [ip] => 78.235.194.139    [p] => 30295)Array(    [n] => ?ü#î5ÆrU