关于PHP读取时间号码问题

public function pai3(&$actionNo, &$actionTime, $time=null){		$this->setTimeNo($actionTime, $time);		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);		if($actionTime >= date('Y-m-d H:i:s', $time)){			$actionNo = date('Yz', $time)-6;		}else{			$actionNo = date('Yz', $time)-6;			$actionTime=date('Y-m-d 18:30', $time);		}	}

上面代码读取的年和号，如201456我想改成2014056增加一位，请问怎么改？

回复讨论(解决方案)

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

能加到我代码上发给我下吗

public function pai3(&$actionNo, &$actionTime, $time=null){		$this->setTimeNo($actionTime, $time);		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);		$year = date('Y', $time);		$day = str_pad(date('z',$time),3,'0',STR_PAD_LEFT);		$times = $year.$day;		if($actionTime >= date('Y-m-d H:i:s', $time)){						$actionNo = $times-6;		}else{			$actionNo = $times-6;			$actionTime=date('Y-m-d 18:30', $time);		}	}