求查询优化步骤
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2024-02-06 08:59:04
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求查询优化方法
请问下面的代码有优化的方法吗
------解决方案--------------------
------解决方案--------------------
请问下面的代码有优化的方法吗
$catalog_1 = "select name from commodity where catalog = 1 ORDER BY rank desc LIMIT 10";
$result_1 = mysql_query($catalog_1);
while($row_1 = mysql_fetch_assoc($result_1)){
$response [] = $row_1;
}
$catalog_2 = "select name from commodity where catalog = 2 ORDER BY rank desc LIMIT 10";
$result_2 = mysql_query($catalog_2);
while($row_2 = mysql_fetch_assoc($result_2)){
$response [] = $row_2;
}
$catalog_3 = "select name from commodity where catalog = 3 ORDER BY rank desc LIMIT 10";
$result_3 = mysql_query($catalog_3);
while($row_3 = mysql_fetch_assoc($result_3)){
$response [] = $row_3;
}
$catalog_4 = "select name from commodity where catalog = 4 ORDER BY rank desc LIMIT 10";
$result_4 = mysql_query($catalog_4);
while($row_4 = mysql_fetch_assoc($result_4)){
$response [] = $row_4;
}
$catalog_5 = "select name from commodity where catalog = 5 ORDER BY rank desc LIMIT 10";
$result_5 = mysql_query($catalog_5);
while($row_5 = mysql_fetch_assoc($result_5)){
$response [] = $row_5;
}
$catalog_6 = "select name from commodity where catalog = 6 ORDER BY rank desc LIMIT 10";
$result_6 = mysql_query($catalog_6);
while($row_6 = mysql_fetch_assoc($result_6)){
$response [] = $row_6;
}
$catalog_7 = "select name from commodity where catalog = 7 ORDER BY rank desc LIMIT 10";
$result_7 = mysql_query($catalog_7);
while($row_7 = mysql_fetch_assoc($result_7)){
$response [] = $row_7;
}
$catalog_8 = "select name from commodity where catalog = 8 ORDER BY rank desc LIMIT 10";
$result_8 = mysql_query($catalog_8);
while($row_8 = mysql_fetch_assoc($result_8)){
$response [] = $row_8;
}
$catalog_11 = "select name from commodity where catalog = 11 ORDER BY rank desc LIMIT 10";
$result_11 = mysql_query($catalog_11);
while($row_11 = mysql_fetch_assoc($result_11)){
$response [] = $row_11;
}
$catalog_10 = "select name from commodity where catalog = 10 ORDER BY rank desc LIMIT 10";
$result_10 = mysql_query($catalog_10);
while($row_10 = mysql_fetch_assoc($result_10)){
$response [] = $row_10;
}
------解决方案--------------------
select name,catalog,rank from commodity c where 10 > (select count(*) from commodity where catalog=c.catalog and id>c.id) and catalog in (1,2,3,4,5,6,7,8,10,11) order by c.catalog,c.rank desc
------解决方案--------------------
function getCataLog($catalog,&$response = array()){
$catalog = "select name from commodity where catalog = ".$catalog." ORDER BY rank desc LIMIT 10";
$result = mysql_query($catalog);
while($row = mysql_fetch_assoc($result)){
$response [] = $row;
}
}
$response = array();
getCataLog(1,$response);
var_dump($response);
getCataLog(2,$response);
var_dump($response);
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