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关于PHP读取时间号码问题

程序员文章站 2024-02-02 21:14:58
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public function pai3(&$actionNo, &$actionTime, $time=null){		$this->setTimeNo($actionTime, $time);		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);		if($actionTime >= date('Y-m-d H:i:s', $time)){			$actionNo = date('Yz', $time)-6;		}else{			$actionNo = date('Yz', $time)-6;			$actionTime=date('Y-m-d 18:30', $time);		}	}

上面代码读取的年和号,如201456我想改成2014056增加一位,请问怎么改?

回复讨论(解决方案)

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

$year = date('Y', time());$day = str_pad(date('z',time()),3,'0',STR_PAD_LEFT);echo $year.$day;

能加到我代码上发给我下吗

public function pai3(&$actionNo, &$actionTime, $time=null){		$this->setTimeNo($actionTime, $time);		//echo $actionTime,' ',date('Y-m-d H:i:s', $time);		$year = date('Y', $time);		$day = str_pad(date('z',$time),3,'0',STR_PAD_LEFT);		$times = $year.$day;		if($actionTime >= date('Y-m-d H:i:s', $time)){						$actionNo = $times-6;		}else{			$actionNo = $times-6;			$actionTime=date('Y-m-d 18:30', $time);		}	}