用二分法求下面方程在（-10，10）的根：2x3-4x2+3x-6=0

用二分法求下面方程在（-10，10）的根：2x3-4x2+3x-6=0

#include <stdio.h>
#include <stdlib.h>
int  f(int x)
{
	return 2 * x*x*x - 4 * x*x + 3*x - 6;
}
int main()
{
	int low = -10;
	int high = 10;
	int mid = (low + (high - low) / 2);
	while (f(mid)!= 0)
	{
		if (f(mid)*f(low) < 0)
		{
			high = mid;
			mid = (low + mid) / 2;
		}
		else
		{
			low = mid;
			mid = (high + mid) / 2;
		}
	}
	printf("%d", mid);
	system("pause");
	return 0;
}

答案
用二分法求下面方程在（-10，10）的根：2x3-4x2+3x-6=0