BestCoder 1st Anniversary

Souvenir

 

 Accepts: 1078

 

 Submissions: 2366

 Time Limit: 2000/1000 MS (Java/Others)

 

 Memory Limit: 262144/262144 K (Java/Others)

Problem Description

Today is the 1st anniversary of BestCoder. Soda, the contest manager, wants to buy a souvenir for each contestant. You can buy the souvenir one by one or set by set in the shop. The price for a souvenir is p yuan and the price for a set of souvenirs if q yuan. There's m souvenirs in one set.

There's n contestants in the contest today. Soda wants to know the minimum cost needed to buy a souvenir for each contestant.

Input

There are multiple test cases. The first line of input contains an integer T (1≤T≤105), indicating the number of test cases. For each test case:

There's a line containing 4 integers n,m,p,q (1≤n,m,p,q≤104).

Output

For each test case, output the minimum cost needed.

Sample Input

2
1 2 2 1
1 2 3 4

Sample Output

1
3

Hint

For the first case, Soda can use 1 yuan to buy a set of 2 souvenirs. For the second case, Soda can use 3 yuan to buy a souvenir.

BestCoder周年纪念赛，趁着还没结束，来一发水题题解（其实是卡题了(/ □ \)囧）

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
    int n,m,p,q,T,flag;
    scanf("%d",&T);
    while(T--)
    {
        scanf("%d%d%d%d",&n,&m,&p,&q);
        if(n<=m)
            flag = min(p*n,q);
        else
        {
            if(p<=q/m)
                flag = n*p;
            else {
                int x = n/m*q;
                int y = (n-n/m*m)*p;
                int z = (n/m+1)*q;
                flag = min(x+y,z);
            }
        }
        printf("%d\n",flag);
    }

    return 0;
}