麻烦帮小弟解决一下这个问题

小弟刚学php不久，写了如下代码，各位大侠见笑了。
代码的大概功能是在当前页面修改页面上显示的图片和文字。文字信息和图片信息存储在mySQL相应的表格里。

Edit item:

---

The file is not an image.'; } else { mysql_query("LOCK TABLES IMAGES WRITE"); mysql_query("LOCK TABLES ITEM WRITE"); if($img_id == 1) { mysql_query("INSERT INTO IMAGES (IMG_NAME, IMG) VALUES ('$image_name', '$image')"); $pic_id = mysql_insert_id(); mysql_query("UPDATE ITEM SET IMG_ID = $pic_id WHERE ITEM_ID = $item_id"); } else { mysql_query("UPDATE IMAGES SET IMG_NAME = '$image_name', IMG = '$image' WHERE IMG_ID = $img_id"); } mysql_query("UNLOCK TABLES"); header("location: " . $_SERVER['REQUEST_URI']); } } } } if(isset($_POST['sub_del_pic'])) { mysql_query("LOCK TABLES ITEM WRITE"); mysql_query("UPDATE ITEM SET IMG_ID = 1 WHERE ITEM_ID = $item_id"); if($img_id != 1) { mysql_query("LOCK TABLES IMAGES WRITE"); mysql_query("DELETE FROM IMAGES WHERE IMG_ID = $img_id"); } mysql_query("UNLOCK TABLES"); header("location: " . $_SERVER['REQUEST_URI']); } ?>

<?php print $name; ?>

---

Congratulations! The item is yours.'; } else { print'

Sorry, the item has been sold!

'; } } else if($status == "NA") { print'

Item is not available yet!

'; } else if($status == "EXPIRE") { print'

Item is expired.

'; } else { date_default_timezone_set('America/New_York'); $curr_date = date("Y-m-d"); $curr_time = date("H:i"); $curr_datetime = "$curr_date $curr_time:00"; print"

Current datetime: $curr_datetime

"; $result = mysql_query("SELECT * FROM ITEM WHERE ITEM_ID = $item_id"); if($result) { $row = mysql_fetch_array($result); $btime = strtotime($row['BEGIN']); $etime = strtotime($row['END']); $date = date("Y-m-d", $etime); $time = date("H:i", $etime); } print'

Change End time:

'; if($_POST['go'] == "Set Time") { $end_date = $_POST['end_date']; $end_time = $_POST['end_time']; $end_time = $end_time.':00'; $end_datetime = strtotime("$end_date $end_time"); $now = strtotime($default_datetime); $problem = false; if ($end_datetime

---

Buy it Now Price:

<?php print $dsc; ?>

问题：第 120行的插入命令为什么不能执行？什么原因导致？怎么解决？

回复讨论(解决方案)

自己多echo输出下看看，查看mysql_query()的返回值是啥？

mysql_query("INSERT INTO IMAGES (IMG_NAME, IMG) VALUES ('$image_name', '$image')");
而
$image = addslashes(file_get_contents($file));

$file 显然是二进制文件
那么仅仅 addslashes 对于 mysql 5 是不行的（mysql 4 可以）
因为大多不可打印的 ASCII 字符都会影响 mysql 的行为

如果一定要将图片数据存放于数据库中，那么要存放图片数据的 base64 编码