高分在线求助XML解析

本帖最后由 HUENKE 于 2013-10-25 15:58:22 编辑

xml

结构为 nodes下面有node下面还有node
我想做三重循环
foreach()
{
存公司名称
foreach()
{
存部门名称
foreach()
{ 存叶子名称}
}
}

请问我该怎么解析呢，

回复讨论(解决方案)

SimpleXML 用过嘛？

SimpleXML 没解析出来
能帮简单调试一下吗

你想要怎样的数据格式？，下面自己组织一下数据结构吧

XML;$xml = new SimpleXMLElement($string);$result = $xml->xpath('//node/@name');while(list( , $node) = each($result)) {    echo '@name: ',$node,"\n";}$result = $xml->xpath('//node/@id');while(list( , $node) = each($result)) {    echo '@id: ',$node,"\n";}$result = $xml->xpath('//node[@type=1]/../@id');while(list( , $node) = each($result)) {    echo '@部门的parent_id: ',$node,"\n";}$result = $xml->xpath('//node[@type=2]/../@id');while(list( , $node) = each($result)) {    echo '@叶子的parent_id: ',$node,"\n";}?>

$s =XML;$xml = simplexml_load_string($s);foreach($xml->node as $node) {  foreach($node->attributes() as $k=>$v) echo "$k => $v\n";  foreach($node->node as $node) {    foreach($node->attributes() as $k=>$v) echo "$k => $v\n";    foreach($node->node as $node) {      foreach($node->attributes() as $k=>$v) echo "$k => $v\n";    }  }}

id => c5569e2c-0f4a-4ec2-86ba-736b79eca18c
name => A公司
type => 0
id => 4f2b55e9-e10a-496b-8bca-60e6f26daee5
name => 部门1
type => 1
id => 363
name => 叶子1
type => 2
playurl => http://XXXXXXX363
id => 0c5ce42f-ba31-4b7a-8173-79ecae4a73ca
name => 部门2
type => 1
id => 241
name => 叶子1
type => 2
playurl => http://xxxxx=241
id => 356
name => 叶子1
type => 2
playurl => xxxxxxxxx=356

就是按他原样的树状结构
如
Ａ公司
　　　　部门１
叶子1

部门2
。。。。

再给你一个吧，自己修改一下就是树状了

XML;$xml = new SimpleXMLElement($string);// var_export($xml);$xmlIterator = new RecursiveIteratorIterator(    new SimpleXMLIterator($string),    RecursiveIteratorIterator::SELF_FIRST);foreach ($xmlIterator as $nodeName => $node) {    echo str_repeat('-', (int)$node['type']);    echo $node['id'], ',', $node['name'], PHP_EOL;}?>

上面#6
$xml = new SimpleXMLElement($string);
这句可以删掉，前面调试的时候留下的