如何使用正则表达式去掉被双引号包裹的数字两边的双引号
程序员文章站
2024-01-28 12:28:40
...
从某云导出数据库表为CSV格式,发现bigint字段两边也被加上了双引号,不应该啊不应该,如何去掉呢?
示例记录:
"31189","aaaa","$P$BFMnptFob/7bmU2o***PNqorSMKzLs0","aaaa","aaa@qq.com","","2015-02-27 02:18:54","","0","oo","0000-00-00"
"31191","bbbb","$P$BeRmQEYPfnOfKrKpF***9osOe3v0aq/","bbb","bbb@qq.com","","2015-02-27 04:23:52","","0","bbb","0000-00-00"
回复内容:
从某云导出数据库表为CSV格式,发现bigint字段两边也被加上了双引号,不应该啊不应该,如何去掉呢?
示例记录:
"31189","aaaa","$P$BFMnptFob/7bmU2o***PNqorSMKzLs0","aaaa","aaa@qq.com","","2015-02-27 02:18:54","","0","oo","0000-00-00"
"31191","bbbb","$P$BeRmQEYPfnOfKrKpF***9osOe3v0aq/","bbb","bbb@qq.com","","2015-02-27 04:23:52","","0","bbb","0000-00-00"
为啥要去掉php 有对应函数
http://php.net/str_getcsv
昂,已经弄了个php版本的处理了
function fucking_aliyun_rds($line){
if(!$line) return;
$line=(string)$line;
$pattern='/^\"\d{1,5}\"/';
$int=$replacement=false;
if(preg_match($pattern, $line, $matches)){
$int=(int)str_replace('"', '', $matches[0]);
}else{
return $line;
}
if($int){
$replacement = $int;
$line=preg_replace('""', '',$line);
$b=preg_replace($pattern, $replacement, $line);
}
$b.="\t";
return $b;
}
$f = fopen ("wp_users.txt", "r");
$ln= 0;
while (! feof ($f)) {
$line= fgets ($f);
/* ++$ln;/
/printf ( $ln);*/
if ($line===FALSE) {
}
else{
$a=fucking_aliyun_rds($line);
echo $a;
}
}
fclose ($f);