PHP读取mysql中图片的有关问题

程序员文章站 2024-01-25 20:58:04

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PHP读取mysql中图片的问题


// pic_database_output.php By Bleakwind

header( "content-type: image/gif");

$Host = "localhost";

$User = "root";

$Password = "";

$Database = "mycicel";


mysqli_connect($Host,$User,$Password) or die("Could not connect:" . mysqli_error());

mysqli_select_db($Database) or die("Could not select database!");


$sql= "SELECT userbase_head FROM `userbase_tables` WHERE `userbase_id`=1";

$result = mysqli_query($sql) or die("Could not perform query!");

$row = mysqli_fetch_array($result);

echo $row['userbase_head'];

?>

通过mysqli无法获得图片，说的是因其本身有错无法显示


// pic_database_output.php By Bleakwind

header( "content-type: image/gif");

$Host = "localhost";

$User = "root";

$Password = "";

$Database = "mycicel";


mysql_connect($Host,$User,$Password) or die("Could not connect:" . mysql_error());

mysql_select_db($Database) or die("Could not select database!");


$sql= "SELECT userbase_head FROM `userbase_tables` WHERE `userbase_id`=1";

$result = mysql_query($sql) or die("Could not perform query!");

$row = mysql_fetch_array($result);

echo $row['userbase_head'];

?>

这段代码可以成功获取，请教大家这是为什么，要通过mysqli应该如何写

php mysql
------解决方案--------------------
先将header注释掉，看报什么错了。