php解析字符串里所有URL地址的方法
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2024-01-25 14:56:58
本文实例讲述了php解析字符串里所有url地址的方法。分享给大家供大家参考。具体如下:
本文实例讲述了php解析字符串里所有url地址的方法。分享给大家供大家参考。具体如下:
<?php // $html = the html on the page // $current_url = the full url that the html came from //(only needed for $repath) // $repath = converts ../ and / and // urls to full valid urls function pagelinks($html, $current_url = "", $repath = false){ preg_match_all("/\<a.+?href=(\"|')(?!javascript:|#)(.+?)(\"|')/i", $html, $matches); $links = array(); if(isset($matches[2])){ $links = $matches[2]; } if($repath && count($links) > 0 && strlen($current_url) > 0){ $pathi = pathinfo($current_url); $dir = $pathi["dirname"]; $base = parse_url($current_url); $split_path = explode("/", $dir); $url = ""; foreach($links as $k => $link){ if(preg_match("/^\.\./", $link)){ $total = substr_count($link, "../"); for($i = 0; $i < $total; $i++){ array_pop($split_path); } $url = implode("/", $split_path) . "/" . str_replace("../", "", $link); }elseif(preg_match("/^\/\//", $link)){ $url = $base["scheme"] . ":" . $link; }elseif(preg_match("/^\/|^.\//", $link)){ $url = $base["scheme"] . "://" . $base["host"] . $link; }elseif(preg_match("/^[a-za-z0-9]/", $link)){ if(preg_match("/^http/", $link)){ $url = $link; }else{ $url = $dir . "/" . $link; } } $links[$k] = $url; } } return $links; } header("content-type: text/plain"); $url = "//www.jb51.net"; $html = file_get_contents($url); // gets links from the page: print_r(pagelinks($html)); // gets links from the page and formats them to a full valid url: print_r(pagelinks($html, $url, true));
希望本文所述对大家的php程序设计有所帮助。
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