php递归遍历多维数组,合并重复值并记录重复次数
程序员文章站
2024-01-20 14:23:16
...
header('Content-type: text/html; charset=utf-8');//以下是原始数组$array = array( 0=>array( 0=>array( 'text' => '体育', 'children' => array( 0=>array( 'text' => '篮球', 'grade' => '1' ), 1=>array( 'text' => '足球', 'grade' => '3' ) ) ), 1=>array( 'text' => '音乐', 'children' => array( 0=>array( 'text' => '唱歌', 'children' => array( 0=>array( 'text' => '儿歌三百首', 'grade' => '1' ) ) ), 1=>array( 'text' => '跳舞', 'grade' => '3' ) ) ) ), 1=>array( 0=>array( 'text' => '体育', 'children' => array( 0=>array( 'text' => '篮球', 'grade' => '2' ), 1=>array( 'text' => '排球', 'grade' => '5' ) ) ), 1=>array( 'text' => '音乐', 'children' => array( 0=>array( 'text' => '唱歌', 'children' => array( 0=>array( 'text' => '儿歌三百首', 'grade' => '4' ) ) ) ) ) ),);//要求：递归遍历原始多维数组，将重复键值合并并累加grade值，以及记录重复次数。如：体育->篮球,经过处理后grade值为1+2=3,重复个数则为2(注:多维数组层级不定)//以下是想要的到的结果$newarray = array( 0=>array( 0=>array( 'text' => '体育', 'children' => array( 0=>array( 'text' => '篮球', 'grade' => '3', 'count' => '2' ), 1=>array( 'text' => '足球', 'grade' => '3', 'count' => '1' ), 2=>array( 'text' => '排球', 'grade' => '5', 'count' => '1' ) ) ), 1=>array( 'text' => '音乐', 'children' => array( 0=>array( 'text' => '唱歌', 'children' => array( 0=>array( 'text' => '儿歌三百首', 'grade' => '5', 'count' => '2' ) ) ), 1=>array( 'text' => '跳舞', 'grade' => '3', 'count' => '1' ) ) ) ));
回复讨论(解决方案)
貌似有性，等高手解决了，学习学习
不需要递归吧。双重循环完全可以搞定。
这就是基础了
不需要递归吧。双重循环完全可以搞定。
但数组的层级是不一定的，实际上有多大5至6级
不需要递归吧。双重循环完全可以搞定。
但数组的层级是不一定的，实际上有多大5至6级
但数组的层级是不一定的，实际上有多达5至6级
你的数据是从哪里来的？
正着做很简单，像你这样反着做是有些难度的
别着急，有空帮你看看
昨天晚上研究这个题目6个小时，最后抱着参考手册找各种数组函数，结果还是没做出来。
你的数据是从哪里来的？
正着做很简单，像你这样反着做是有些难度的
别着急，有空帮你看看
多谢版主
昨天晚上研究这个题目6个小时，最后抱着参考手册找各种数组函数，结果还是没做出来。
不才，我花了2天时间也还是没能找着出路
给个思路：先降维
function untree($ar, $key='children', $deep=0, $paren='') { $res = array(); foreach((array)$ar as $v) { if(is_numeric(key($v))) { $res = array_merge($res, untree($v, $key, $deep+1, $paren)); continue; } $v['deep'] = $deep; $v['paren'] = $paren; if(isset($v[$key])) { $t = $v[$key]; $pa = $v['text']; unset($v[$key]); } $res[] = $v; if(! empty($t)) $res = array_merge($res, untree($t, $key, $deep+1, $pa)); } return $res;}print_r(untree($array)); 得
Array
(
[0] => Array
(
[text] => 体育
[deep] => 1
[paren] =>
)
[1] => Array
(
[text] => 篮球
[grade] => 1
[deep] => 2
[paren] => 体育
)
[2] => Array
(
[text] => 足球
[grade] => 3
[deep] => 2
[paren] => 体育
)
[3] => Array
(
[text] => 音乐
[deep] => 1
[paren] =>
)
[4] => Array
(
[text] => 唱歌
[deep] => 2
[paren] => 音乐
)
[5] => Array
(
[text] => 儿歌三百首
[grade] => 1
[deep] => 3
[paren] => 唱歌
)
[6] => Array
(
[text] => 跳舞
[grade] => 3
[deep] => 2
[paren] => 音乐
)
[7] => Array
(
[text] => 儿歌三百首
[grade] => 1
[deep] => 3
[paren] => 唱歌
)
[8] => Array
(
[text] => 体育
[deep] => 1
[paren] =>
)
[9] => Array
(
[text] => 篮球
[grade] => 2
[deep] => 2
[paren] => 体育
)
[10] => Array
(
[text] => 排球
[grade] => 5
[deep] => 2
[paren] => 体育
)
[11] => Array
(
[text] => 音乐
[deep] => 1
[paren] =>
)
[12] => Array
(
[text] => 唱歌
[deep] => 2
[paren] => 音乐
)
[13] => Array
(
[text] => 儿歌三百首
[grade] => 4
[deep] => 3
[paren] => 唱歌
)
)
你的数据是从哪里来的？
正着做很简单，像你这样反着做是有些难度的
别着急，有空帮你看看
数据是通过另一个封装函数返回的（我不能修改封装函数）
给个思路：先降维
function untree($ar, $key='children', $deep=0, $paren='') { $res = array(); foreach((array)$ar as $v) { if(is_numeric(key($v))) { $res = array_merge($res, untree($v, $key, $deep+1, $paren)); continue; } $v['deep'] = $deep; $v['paren'] = $paren; if(isset($v[$key])) { $t = $v[$key]; $pa = $v['text']; unset($v[$key]); } $res[] = $v; if(! empty($t)) $res = array_merge($res, untree($t, $key, $deep+1, $pa)); } return $res;}print_r(untree($array)); 得
Array
(
[0] => Array
(
[text] => 体育
[deep] => 1
[paren] =>
)
[1] => Array
(
[text] => 篮球
[grade] => 1
[deep] => 2
[paren] => 体育
)
[2] => Array
(
[text] => 足球
[grade] => 3
[deep] => 2
[paren] => 体育
)
[3] => Array
(
[text] => 音乐
[deep] => 1
[paren] =>
)
[4] => Array
(
[text] => 唱歌
[deep] => 2
[paren] => 音乐
)
[5] => Array
(
[text] => 儿歌三百首
[grade] => 1
[deep] => 3
[paren] => 唱歌
)
[6] => Array
(
[text] => 跳舞
[grade] => 3
[deep] => 2
[paren] => 音乐
)
[7] => Array
(
[text] => 儿歌三百首
[grade] => 1
[deep] => 3
[paren] => 唱歌
)
[8] => Array
(
[text] => 体育
[deep] => 1
[paren] =>
)
[9] => Array
(
[text] => 篮球
[grade] => 2
[deep] => 2
[paren] => 体育
)
[10] => Array
(
[text] => 排球
[grade] => 5
[deep] => 2
[paren] => 体育
)
[11] => Array
(
[text] => 音乐
[deep] => 1
[paren] =>
)
[12] => Array
(
[text] => 唱歌
[deep] => 2
[paren] => 音乐
)
[13] => Array
(
[text] => 儿歌三百首
[grade] => 4
[deep] => 3
[paren] => 唱歌
)
)
其实原始数组有记录id ,pid值的
那你就把数据特完整了
$array=array( '0' => array( '0' => array( 'id' => 87073074, 'pid' => 0, 'text' => '白田最新??', 'children' => array( '0' => array( 'id' => 67852256, 'pid' => 87073074, 'text' => '??知?', 'children' => array( '0' => array( 'id' => 44740741, 'pid' => 67852256, 'text' => '?能?健康', 'children' => array( '0' => array( 'id' => 66256396, 'pid' => 44740741, 'text' => '小肌肉', 'children' => array( '0' => array( 'id' => 71852852, 'pid' => 66256396, 'text' => '掌握?手??能力', 'children' => array( '0' => array( 'id' => 84741741, 'text' => '能摺?包', 'grade' => 1 ) ) ) ) ) ) ), '1' => array( 'id' => 32518528, 'pid' => 67852256, 'text' => '?文', 'children' => array( '0' => array( 'id' => 18185185, 'pid' => 32518528, 'text' => '?', 'children' => array( '0' => array( 'id' => 35256896, 'pid' => 18185185, 'text' => '能理解故事?容要?', 'children' => array( '0' => array( 'id' => 69295296, 'text' => '能理解故事?容要?', 'grade' => 1 ) ) ), '1' => array( 'id' => 54740741, 'pid' => 18185185, 'text' => '能\'?\',指示?行??和活?', 'children' => array( '0' => array( 'id' => 93629639, 'text' => '能\'?\',指示?行活?和??', 'grade' => 1 ) ) ) ) ) ) ) ) ) ) ) ), '1' => array( '0' => array( 'id' => 87073074, 'pid' => 0, 'text' => '白田最新??', 'children' => array( '0' => array( 'id' => 67852256, 'pid' => 87073074, 'text' => '??知?', 'children' => array( '0' => array( 'id' => 44740741, 'pid' => 67852256, 'text' => '?能?健康', 'children' => array( '0' => array( 'id' => 66256396, 'pid' => 44740741, 'text' => '小肌肉', 'children' => array( '0' => array( 'id' => 71852852, 'pid' => 66256396, 'text' => '掌握?手??能力', 'children' => array( '0' => array(