程序员 - PHP计算出两个年份的相差的月份,注意我只要月份,比如 "2013-07-03" "2014-03-12"
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2024-01-17 18:24:52
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PHP计算出两个年份的相差的月份,注意我只要月份,比如 "2013-07-03" "2014-03-12",他们相差的8个月,那么你的函数中必须返回8,注意代码冗余
回复内容:
PHP计算出两个年份的相差的月份,注意我只要月份,比如 "2013-07-03" "2014-03-12",他们相差的8个月,那么你的函数中必须返回8,注意代码冗余
上一个回答没考虑年份差(不过题主强调了只需要月份),这里补上 @ 2014-03-27 10:06:25:
$time_begin = strtotime("2012-07-03");
$time_end = strtotime("2014-03-12");
$time_differ = $time_end - $time_begin;
$year_differ = date('Y', $time_differ);
$month_differ = date('m', $time_differ);
$result = 12*intval($year_differ-1970)+intval($month_differ)-1;
$time_begin = strtotime("2013-07-03");
$time_end = strtotime("2014-03-12");
$time_differ = $time_end - $time_begin;
$month_differ = date('m', $time_differ);
$result = intval($month_differ)-1;
亲测可行。
$d1 = new DateTime('2013-07-03');
$d2 = new DateTime('2014-03-12');
$diff=$d2->diff($d1);
echo ($diff->y*12)+$diff->m;