PHP类与对象中的private访问控制的疑问_PHP
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2024-01-16 15:01:58
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复制代码 代码如下:
class Bar
{
public function test() {
$this->testPrivate();
$this->testPublic();
}
public function testPublic() {
echo "Bar::testPublic\n";
}
private function testPrivate() {
echo "Bar::testPrivate\n";
}
}
class Foo extends Bar
{
public function testPublic() {
echo "Foo::testPublic\n";
}
private function testPrivate() {
echo "Foo::testPrivate\n";
}
}
$myFoo = new foo();
$myFoo->test(); // Bar::testPrivate
// Foo::testPublic
为啥第一行会输出Bar::testPrivate呢?
一些资料:
http://www.bitsCN.com/article/31709.htm
还有php官网上,关于这段代码的贡献者回复中,也找到了一条:
http://www.php.net/manual/zh/language.oop5.visibility.php#87413
class Bar
{
public function test() {
$this->testPrivate();
$this->testPublic();
}
public function testPublic() {
echo "Bar::testPublic\n";
}
private function testPrivate() {
echo "Bar::testPrivate\n";
}
}
class Foo extends Bar
{
public function testPublic() {
echo "Foo::testPublic\n";
}
private function testPrivate() {
echo "Foo::testPrivate\n";
}
}
$myFoo = new foo();
$myFoo->test(); // Bar::testPrivate
// Foo::testPublic
为啥第一行会输出Bar::testPrivate呢?
一些资料:
http://www.bitsCN.com/article/31709.htm
还有php官网上,关于这段代码的贡献者回复中,也找到了一条:
http://www.php.net/manual/zh/language.oop5.visibility.php#87413
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