medoo框架如何将JSON插入到数据库?
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2023-12-31 19:02:46
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刚开始学习PHP,medoo的文档insert中提到的插入多条数据:
$last_user_id = $database->insert("account", [
[
"user_name" => "foo",
"email" => "foo@bar.com",
"age" => 25,
"city" => "New York",
"(JSON) lang" => ["en", "fr", "jp", "cn"]
],
[
"user_name" => "bar",
"email" => "bar@foo.com",
"age" => 14,
"city" => "*",
"(JSON) lang" => ["en", "jp", "cn"]
]
]);
请教大神,该如何将post来的数据插入到数据库?能不能给个简单的DEMO?万分感谢!
post来的数据大致如下:
{
"name" : "xiaoming",
"age" : 20
},
{
"name" : "lihong",
"age" : 25
}
我自己尝试了好多次,都没成功,希望大神能解答,谢谢
回复内容:
刚开始学习PHP,medoo的文档insert中提到的插入多条数据:
$last_user_id = $database->insert("account", [
[
"user_name" => "foo",
"email" => "foo@bar.com",
"age" => 25,
"city" => "New York",
"(JSON) lang" => ["en", "fr", "jp", "cn"]
],
[
"user_name" => "bar",
"email" => "bar@foo.com",
"age" => 14,
"city" => "*",
"(JSON) lang" => ["en", "jp", "cn"]
]
]);
请教大神,该如何将post来的数据插入到数据库?能不能给个简单的DEMO?万分感谢!
post来的数据大致如下:
{
"name" : "xiaoming",
"age" : 20
},
{
"name" : "lihong",
"age" : 25
}
我自己尝试了好多次,都没成功,希望大神能解答,谢谢
如果不是表单提交,也就是说 request header 的 content-type 不等于 application/x-www-form-urlencoded 或者 multipart/form-data 的话,PHP 是没办法自动解析你传递过来的数据并赋值到 $_POST 去的。这个时候你需要使用 php://input
获取所有传递过来的内容并手动解析数据。
假设你传过来的数据是:
[
{"name": "xiaoming", "age": 20},
{"name": "lihong", "age": 25}
]
那么你可以这么写:
$_POST = json_decode( file_get_contents('php://input'), true);
$last_user_id = $database->insert("account", $_POST);
除了medoo以外,php还有什么好用的数据库工具类?