open 动态修改img的onclick事件示例代码_javascript技巧
程序员文章站
2023-12-24 20:22:09
...
复制代码 代码如下:
var imgsrc = document.getElementById("imgsrc").getElementsByTagName('img');
imgsrc[0].style.cursor="hand";
imgsrc[0].onclick = new Function( "openArticle('/RssCommServlet?catalogid=29')");
imgsrc[1].style.cursor="hand";
imgsrc[1].onclick = new Function( "openArticle('/RssCommServlet?catalogid=30')");
imgsrc[2].style.cursor="hand";
imgsrc[2].onclick = new Function( "openArticle('/RssCommServlet?catalogid=31')");