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javaweb中ajax请求后台servlet(实例)

程序员文章站 2023-12-19 17:54:28
废话不多说,直接上代码 public class dzfp_jdbc extends httpservlet{ private static final l...

废话不多说,直接上代码

public class dzfp_jdbc extends httpservlet{
  private static final long serialversionuid = 1l;

  public static connection conn; 
  public static resultset rs = null ;  
  public static preparedstatement ps = null ;
  private static string url = "jdbc:oracle:thin:@192.168.100.11:1111:crm";
  private static string name = "name";
  private static string pwd = "pwd";

  protected void dopost(httpservletrequest request, httpservletresponse response) throws servletexception, ioexception {

    /*preparedstatement ps;
    resultset rs = null;*/
    response.setcharacterencoding("utf-8");
    request.setcharacterencoding("utf-8");
    response.setheader("content-type", "text/html;charset=utf-8");

    printwriter out = response.getwriter();

    ***********

    out.print("{\"errorno\":[{\"list\":error}]}");
  }
}


$.ajax({ 
  type: "post", 
  url: "dzfp_jdbc", 
  datatype: "text", 

    data : {
      taxcode : taxcode,
      mobilenum : mobilenum
  },
  timeout : 50000,

    success: function (data) { 
  var jsonobjs = eval("(" + data + ")");
  var list = jsonobjs.errorno[0].list;


    }, 
  error: function() {
      alert("网络异常,请稍后重试");

  } 
});

<servlet>
  <servlet-name>dzfp_jdbc</servlet-name>
  <servlet-class>
  weishijiestudio.hangxinwx.servlet.dzfp_jdbc
  </servlet-class>
</servlet>
<servlet-mapping>
  <servlet-name>dzfp_jdbc</servlet-name>
  <url-pattern>/dzfp_jdbc</url-pattern>
</servlet-mapping>

以上这篇javaweb中ajax请求后台servlet(实例)就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持。

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