C#重载运算符详解
本文较为详细的描述了重载运算符的方法。一般来说,重载运算符在实际的项目开发中会经常的用到,但如果某些自定义类型通过简短几行代码重载一些常用的运算符(如:+-*/),就能让编程工作带来方便;重载运算符就是告诉编译器+-*/等运算符对于自定义类型进行什么样的操作,在代码中需要注意几点。
一、尽可能的不要改变运算符本身的含义
二、所有的运算符重载都必须声明为public和static
三、不同于扩展方法,所重载的方法必须是在被重载的类型内部,且用关键字operator
c#中的两个字符串相加,实际上是连接两个字符串,假如有两个employeedetail类型相加得到一个employeecollection集合,如:
employeedetail a,b; .... employeecollection collection = a+b;
当编译器遇到上面的代码时就会自动调用employeedetail类上标有operator +的静态方法,并将两个操作数a和b作为参数传递给对于的方法,该方法需要方法一个值赋给collection,假设employeedetail类有三个属性分别是firstname,middlename,lastname,还重写了tostring方法返回一个连接这三个名称的字符串,代码如:
[serializable] public class employeedetail { public string firstname { get; set; } public string middlename { get; set; } public string lastname { set;get; } public override string tostring() { return string.format("{0}{1}{2}{3}{4}", firstname, string.isnullorwhitespace(middlename) ? null : "." , middlename , string.isnullorwhitespace(lastname) ? null : ".", lastname).trim(); } }
下面的代码为“+”运算符提供支持的运算符重载:
public static employeecollection operator +(employeedetail a, employeedetail b) { return new employeecollection() { a, b }; }
ok,给employeedetail类加上这样的一个方法之后,我们就可以像下面那个写代码了:
employeecollection collection = new employeedetail(){firstname="jackson",lastname="bruce"} + new employeedetail(){firstname="michael",lastname="jackson"} ;
但是这样还不够完美,假设a,b,c都是employeedetail类型,下面的代码会抛出一个编译错误:
employeecollection collection = a + b + c;
为什么编译不通过呢?大家都知道除了赋值运算符外表达式是从左到右执行的,a+b返回的是employeecollection类型,employeecollection类型并没有重载“+”运算符,编译器不知道要执行什么操作,所以我们还有下面的两个方法:
public static employeecollection operator +(employeecollection collection, employeedetail a) { collection.add(a); return collection; } public static employeecollection operator +(employeedetail a, employeecollection collection) { return collection + a; }
这看起来似乎已经很完美了,但我们还可以做得更好一些,比如要将字符串“jackson.bruce”直接隐式转换为employeedetail类型,也就是说可以将“jackson.bruce"这种格式的字符串直接赋给employeedetail类型的对象,如:employeedetail employee= “jackson.bruce",那么就需要重载隐式类型转换运算符了,代码如下:
/// <summary> /// 隐式类型转换 /// </summary> /// <param name="name"></param> /// <returns></returns> public static implicit operator employeedetail(string name) { /// 其实在这里可以写一个正则表达式检查name的字符串格式是否合法,如果不合法就抛出异常 /// string[] arr; return string.isnullorwhitespace(name) ? null : new employeedetail() { firstname = (arr = name.trim().split('.'))[0] , lastname = arr.length > 1 ? arr[arr.length > 2 ? 2 : 1] : null, middlename = arr.length > 2 ? arr[1] : null }; } public static employeecollection operator +(employeedetail a, string b) { return new employeecollection() { a, b }; }
看到这里您是不是迫不及待地想试试看,ok写个控制台程序来测试一下:
static void main(string[] args) { employeedetail employee = "jackson.bruce"; console.writeline("firstname={0},middlenam={1},lastname={2}", employee.firstname, employee.middlename, employee.lastname); console.writeline("tostring={0}", employee); console.writeline(); employeecollection collection = "michael.jackson" + employee; collection += "bruce.lee"; foreach (var e in collection) { console.writeline(e); } console.writeline(); collection -= employee; foreach (var e in collection) { console.writeline(e); } console.writeline("===end==="); console.read(); }
运行结果如下图所示:
全部代码,里面还包含其他运算符的重载,这里就不再介绍了,赶紧动手测试一下吧:
using system; using system.collections.generic; using system.linq; using system.text; namespace 重载运算符 { [serializable] public class employeedetail { public string firstname { get; set; } public string middlename { get; set; } public string lastname { set;get; } public static employeecollection operator +(employeedetail a, employeedetail b) { return new employeecollection() { a, b }; } public static employeecollection operator +(employeecollection collection, employeedetail a) { collection.add(a); return collection; } public static employeecollection operator +(employeedetail a, employeecollection collection) { return collection + a; } /// <summary> /// 隐式类型转换 /// </summary> /// <param name="name"></param> /// <returns></returns> public static implicit operator employeedetail(string name) { string[] arr; return string.isnullorwhitespace(name) ? null : new employeedetail() { firstname = (arr = name.trim().split('.'))[0] , lastname = arr.length > 1 ? arr[arr.length > 2 ? 2 : 1] : null, middlename = arr.length > 2 ? arr[1] : null }; } public static employeecollection operator +(employeedetail a, string b) { return new employeecollection() { a, b }; } public override string tostring() { return string.format("{0}{1}{2}{3}{4}", firstname, string.isnullorwhitespace(middlename) ? null : "." , middlename , string.isnullorwhitespace(lastname) ? null : ".", lastname).trim(); } } public class employeecollection : list<employeedetail> { public static employeecollection operator +(employeecollection a, string b) { a.add(b); return a; } public static employeecollection operator +(string b, employeecollection a) { return a + b; } public static employeecollection operator -(employeecollection a, employeedetail b) { a.remove(b); return a; } } class program { static void main(string[] args) { employeedetail employee = "jackson.bruce"; console.writeline("firstname={0},middlenam={1},lastname={2}", employee.firstname, employee.middlename, employee.lastname); console.writeline("tostring={0}", employee); console.writeline(); employeecollection collection = "michael.jackson" + employee; collection += "bruce.lee"; foreach (var e in collection) { console.writeline(e); } console.writeline(); collection -= employee; foreach (var e in collection) { console.writeline(e); } console.writeline("===end==="); console.read(); } } }