Kotlin 基础教程之数组容器
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2023-12-15 12:17:28
kotlin 基础教程之数组容器
arrays
kotlin 标准库提供了arrayof()创建数组, **arrayof创建特定类型数组
val array...
kotlin 基础教程之数组容器
arrays
kotlin 标准库提供了arrayof()创建数组, **arrayof创建特定类型数组
val array = arrayof(1, 2, 3) val countries = arrayof("uk", "germany", "italy") val numbers = intarrayof(10, 20, 30) val array1 = array(10, { k -> k * k }) val longarray = emptyarray<long>() val studentarray = array<student>(2) studentarray[0] = student("james")
和java不一样,kotlin 的数组是容器类, 提供了 bytearray, chararray, shortarray, intarray, longarray, booleanarray, floatarray, and doublearray。
lists
list是有序容器,kotlin 标准库通过listof()创建list
val intlist: list<int> = listof(20, 5, 10) val emptylist: list<string> = emptylist<string>() val nonnulls: list<string> = listofnotnull<string>(null, "a", "b", "c") val doublelist: arraylist<double> = arraylistof(84.88, 100.25, 999.99)
其中,intlist, emptylist, nonnulls是只读的实例,要修改这些list,需要进行类型转换
(intlist as abstractlist<int>).set(0, 30) (nonnulls as java.util.arraylist).addall(arrayof("x", "y"))
maps
map是<key, value>容器, kotlin提供mapof创建map
val map = mapof("a" to 1, "b" to 2, "c" to 3) val value = map.get(b) val states: mutablemap<string, string>= mutablemapof("al" to "alabama", "ak" to "alaska", "az" to "arizona") val customers: java.util.hashmap<int, customer> = hashmapof(1 to customer("dina", "kreps", 1), 2 to customer("andy", "smith", 2)) val linkedhashmap: java.util.linkedhashmap<string, string> = linkedmapof("red" to "#ff0000","azure" to "#f0ffff","white" to "#ffffff") val sortedmap: java.util.sortedmap<int, string> = sortedmapof(4 to "d", 1 to "a", 3 to "c", 2 to "b")
sets
set是没有重复项的容器, kotlin提供setof创建set
val intset: set<int> = setof(1, 21, 21, 2, 6, 3, 2) //1,21,2,6,3 val hashset: java.util.hashset<book> = hashsetof( book("jules verne", "around the world in 80 days paperback", 2014, "978-1503215153"), book("jules verne", "around the world in 80 days paperback", 2014, "978-1503215153")) val sortedintegers: java.util.treeset<int> = sortedsetof(11, 0, 9, 11, 9, 8)
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