C#实现农历日历的方法
本文实例讲述了c#实现农历日历的方法。分享给大家供大家参考。
具体实现方法如下：
private static string []tiangan = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
//地支
private static string []dizhi = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
//十二生肖
private static string []shengxiao = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"};
//农历日期
private static string []dayname = {"*","初一","初二","初三","初四","初五","初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"};
//农历月份
private static string []monthname = {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"};
//公历月计数天
private static int []monthadd = {0,31,59,90,120,151,181,212,243,273,304,334};
//农历数据
private static int []lunardata = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438 ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402 ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738 ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762 ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413 ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395 ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031 ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222 ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709 ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
/// <summary>
/// 获取对应日期的农历
///
/// </summary>
/// <param name="dtday">公历日期</param>
///
///<returns></returns>
public string getlunarcalendar(datetime dtday)
{
string syear = dtday.year.tostring(); string smonth = dtday.month.tostring();
string sday = dtday.day.tostring();
int year;
int month;
int day;
try {
year = int.parse(syear);
month = int.parse(smonth);
day = int.parse(sday);
}
catch {
year = datetime.now.year;
month = datetime.now.month;
day = datetime.now.day;
}
int nthedate;
int nisend;
int k, m, n, nbit, i;
string calendar = string.empty;
//计算到初始时间1921年2月8日的天数：1921-2-8(正月初一)
nthedate = (year - 1921) * 365 + (year - 1921) / 4 + day + monthadd[month - 1] - 38;
if ((year % 4 == 0) && (month > 2)) nthedate += 1;
//计算天干，地支，月，日
nisend = 0; m = 0; k = 0; n = 0;
while (nisend != 1)
{
if (lunardata[m] < 4095) k = 11; else k = 12; n = k; while (n >= 0)
{ //获取lunardata[m]的第n个二进制位的值
nbit = lunardata[m];
for (i = 1; i < n + 1; i++) nbit = nbit / 2;
nbit = nbit % 2;
if (nthedate <= (29 + nbit)) { nisend = 1; break; }
nthedate = nthedate - 29 - nbit; n = n - 1;
}
if (nisend == 1) break; m = m + 1;
}
year = 1921 + m; month = k - n + 1; day = nthedate;
#region 格式化日期显示为三月廿四
if (k == 12)
{
if (month == lunardata[m] / 65536 + 1)
month = 1 - month;
else if (month > lunardata[m] / 65536 + 1)
month = month - 1;
}
//生肖//
calendar = shengxiao[(year - 4) % 60 % 12].tostring() + "年 ";
// // //天干// //
calendar += tiangan[(year - 4) % 60 % 10].tostring();
// // //地支// //
calendar += dizhi[(year - 4) % 60 % 12].tostring() + " ";
//// //农历月//
if (month < 1)
//
calendar += "闰" + monthname[-1 * month].tostring() + "月";
else
calendar += monthname[month].tostring() + "月";
//// //农历日//
calendar += dayname[day].tostring() + "日";////
return calendar;////
#endregion
}
希望本文所述对大家的c#程序设计有所帮助。