asp.net(C#)实现功能强大的时间日期处理类完整实例
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2023-12-13 14:00:10
本文实例讲述了asp.net(c#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下:
using system;
using system.dat...
本文实例讲述了asp.net(c#)实现功能强大的时间日期处理类。分享给大家供大家参考,具体如下:
using system; using system.data; using system.configuration; using system.web; using system.web.security; using system.web.ui; using system.web.ui.webcontrols; using system.web.ui.webcontrols.webparts; using system.web.ui.htmlcontrols; namespace mscl { /// <summary> /// 时间日期处理类 /// </summary> public class datetimehelper { #region 返回本年有多少天 /// <summary>返回本年有多少天</summary> /// <param name="iyear">年份</param> /// <returns>本年的天数</returns> public static int getdaysofyear(int iyear) { int cnt = 0; if (isruyear(iyear)) { //闰年多 1 天 即:2 月为 29 天 cnt = 366; } else { //--非闰年少1天 即:2 月为 28 天 cnt = 365; } return cnt; } #endregion #region 返回本年有多少天 /// <summary>本年有多少天</summary> /// <param name="dt">日期</param> /// <returns>本天在当年的天数</returns> public static int getdaysofyear(datetime idt) { int n; //取得传入参数的年份部分,用来判断是否是闰年 n = idt.year; if (isruyear(n)) { //闰年多 1 天 即:2 月为 29 天 return 366; } else { //--非闰年少1天 即:2 月为 28 天 return 365; } } #endregion #region 返回本月有多少天 /// <summary>本月有多少天</summary> /// <param name="iyear">年</param> /// <param name="month">月</param> /// <returns>天数</returns> public static int getdaysofmonth(int iyear, int month) { int days = 0; switch (month) { case 1: days = 31; break; case 2: if (isruyear(iyear)) { //闰年多 1 天 即:2 月为 29 天 days = 29; } else { //--非闰年少1天 即:2 月为 28 天 days = 28; } break; case 3: days = 31; break; case 4: days = 30; break; case 5: days = 31; break; case 6: days = 30; break; case 7: days = 31; break; case 8: days = 31; break; case 9: days = 30; break; case 10: days = 31; break; case 11: days = 30; break; case 12: days = 31; break; } return days; } #endregion #region 返回本月有多少天 /// <summary>本月有多少天</summary> /// <param name="dt">日期</param> /// <returns>天数</returns> public static int getdaysofmonth(datetime dt) { //--------------------------------// //--从dt中取得当前的年,月信息 --// //--------------------------------// int year, month, days = 0; year = dt.year; month = dt.month; //--利用年月信息,得到当前月的天数信息。 switch (month) { case 1: days = 31; break; case 2: if (isruyear(year)) { //闰年多 1 天 即:2 月为 29 天 days = 29; } else { //--非闰年少1天 即:2 月为 28 天 days = 28; } break; case 3: days = 31; break; case 4: days = 30; break; case 5: days = 31; break; case 6: days = 30; break; case 7: days = 31; break; case 8: days = 31; break; case 9: days = 30; break; case 10: days = 31; break; case 11: days = 30; break; case 12: days = 31; break; } return days; } #endregion #region 返回当前日期的星期名称 /// <summary>返回当前日期的星期名称</summary> /// <param name="dt">日期</param> /// <returns>星期名称</returns> public static string getweeknameofday(datetime idt) { string dt, week = ""; dt = idt.dayofweek.tostring(); switch (dt) { case "mondy": week = "星期一"; break; case "tuesday": week = "星期二"; break; case "wednesday": week = "星期三"; break; case "thursday": week = "星期四"; break; case "friday": week = "星期五"; break; case "saturday": week = "星期六"; break; case "sunday": week = "星期日"; break; } return week; } #endregion #region 返回当前日期的星期编号 /// <summary>返回当前日期的星期编号</summary> /// <param name="dt">日期</param> /// <returns>星期数字编号</returns> public static string getweeknumberofday(datetime idt) { string dt, week = ""; dt = idt.dayofweek.tostring(); switch (dt) { case "mondy": week = "1"; break; case "tuesday": week = "2"; break; case "wednesday": week = "3"; break; case "thursday": week = "4"; break; case "friday": week = "5"; break; case "saturday": week = "6"; break; case "sunday": week = "7"; break; } return week; } #endregion #region 判断当前日期所属的年份是否是闰年,私有函数 /// <summary>判断当前日期所属的年份是否是闰年,私有函数</summary> /// <param name="dt">日期</param> /// <returns>是闰年:true ,不是闰年:false</returns> private static bool isruyear(datetime idt) { //形式参数为日期类型 //例如:2003-12-12 int n; n = idt.year; if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0)) { return true; } else { return false; } } #endregion #region 判断当前年份是否是闰年,私有函数 /// <summary>判断当前年份是否是闰年,私有函数</summary> /// <param name="dt">年份</param> /// <returns>是闰年:true ,不是闰年:false</returns> private static bool isruyear(int iyear) { //形式参数为年份 //例如:2003 int n; n = iyear; if ((n % 400 == 0) || (n % 4 == 0 && n % 100 != 0)) { return true; } else { return false; } } #endregion #region 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期 /// <summary> /// 将输入的字符串转化为日期。如果字符串的格式非法,则返回当前日期。 /// </summary> /// <param name="strinput">输入字符串</param> /// <returns>日期对象</returns> public static datetime convertstringtodate(string strinput) { datetime odatetime; try { odatetime = datetime.parse(strinput); } catch (exception) { odatetime = datetime.today; } return odatetime; } #endregion #region 将日期对象转化为格式字符串 /// <summary> /// 将日期对象转化为格式字符串 /// </summary> /// <param name="odatetime">日期对象</param> /// <param name="strformat"> /// 格式: /// "shortdate"===短日期 /// "longdate"==长日期 /// 其它====自定义格式 /// </param> /// <returns>日期字符串</returns> public static string convertdatetostring(datetime odatetime, string strformat) { string strdate = ""; try { switch (strformat.toupper()) { case "shortdate": strdate = odatetime.toshortdatestring(); break; case "longdate": strdate = odatetime.tolongdatestring(); break; default: strdate = odatetime.tostring(strformat); break; } } catch (exception) { strdate = odatetime.toshortdatestring(); } return strdate; } #endregion #region 判断是否为合法日期,必须大于1800年1月1日 /// <summary> /// 判断是否为合法日期,必须大于1800年1月1日 /// </summary> /// <param name="strdate">输入日期字符串</param> /// <returns>true/false</returns> public static bool isdatetime(string strdate) { try { datetime odate = datetime.parse(strdate); if (odate.compareto(datetime.parse("1800-1-1")) > 0) return true; else return false; } catch (exception) { return false; } } #endregion #region 获取两个日期之间的差值 可返回年 月 日 小时 分钟 秒 /// <summary> /// 获取两个日期之间的差值 /// </summary> /// <param name="howtocompare">比较的方式可为:year month day hour minute second</param> /// <param name="startdate">开始日期</param> /// <param name="enddate">结束日期</param> /// <returns>时间差</returns> public static double datediff(string howtocompare, datetime startdate, datetime enddate) { double diff = 0; try { timespan ts = new timespan(enddate.ticks - startdate.ticks); switch (howtocompare.tolower()) { case "year": diff = convert.todouble(ts.totaldays / 365); break; case "month": diff = convert.todouble((ts.totaldays / 365) * 12); break; case "day": diff = convert.todouble(ts.totaldays); break; case "hour": diff = convert.todouble(ts.totalhours); break; case "minute": diff = convert.todouble(ts.totalminutes); break; case "second": diff = convert.todouble(ts.totalseconds); break; } } catch (exception) { diff = 0; } return diff; } #endregion #region 计算两个日期之间相差的工作日天数 /// <summary> /// 计算两个日期之间相差的工作日天数 /// </summary> /// <param name="dtstart">开始日期</param> /// <param name="dtend">结束日期</param> /// <param name="flag">是否除去周六,周日</param> /// <returns>int</returns> public static int calculateworkingdays(datetime dtstart, datetime dtend, bool flag) { int count = 0; for (datetime dttemp = dtstart; dttemp < dtend; dttemp = dttemp.adddays(1)) { if (flag) { if (dttemp.dayofweek != dayofweek.saturday && dttemp.dayofweek != dayofweek.sunday) { count++; } } else { count++; } } return count; } #endregion } }
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