C#结合JavaScript实现秒杀倒计时的方法

本文实例讲述了c#结合javascript实现秒杀倒计时的方法。分享给大家供大家参考。具体如下：

最近做个秒杀活动，要用到倒计时。要求每周三上午10:00开始倒计时

private string dtime() 
{ 
 byte tempb = (byte)datetime.now.dayofweek; 
 byte daybyte = (byte)dayofweek.wednesday; 
 datetime wednesdaynow = datetime.now.adddays(daybyte - tempb);
 //本星期三 
 datetime returntime = new datetime (); 
 if (datetime.now.dayofweek < wednesdaynow.dayofweek) 
 { 
  //当前星期小于本星期三 获取本周星期三 
  returntime = new datetime(wednesdaynow.year,wednesdaynow.month,wednesdaynow.day,10,0,0);
 } 
 else 
 { 
  //当前星期大于本星期三 获取下周星期三 
  datetime nextwednesday = wednesdaynow.adddays(7);//下周三 
  returntime = new datetime(nextwednesday.year,nextwednesday.month,nextwednesday.day,10,0,0);
 } 
 return returntime.tostring() 
}

这个方法可以得到每周三的时间，然后用js对该时间进行倒计时

$(document).ready(function() {
 $('body').everytime('1s', function() {
 var nowdate = new date();
 var enddate = new date($("#sp_next").html().replace(//-/g, "//"));
 //这个时间是上个方法返回的时间
 var timeold = enddate.gettime() - nowdate.gettime();
 var sectimeold = timeold / 1000
 var secondsold = math.floor(sectimeold);
 var msperday = 24 * 60 * 60 * 1000
 var e_daysold = timeold / msperday
 var daysold = math.floor(e_daysold);
 var e_hrsold = (e_daysold - daysold) * 24 + (daysold * 24);
 var hrsold = math.floor(e_hrsold);
 var e_minsold = (e_hrsold - hrsold) * 60;
 var minsold = math.floor((e_hrsold - hrsold) * 60);
 var seconds = math.floor((e_minsold - minsold) * 60);
 if (hrsold > 0 && hrsold < 10) { hrsold = "0" + hrsold; }
 if (minsold < 10) { minsold = "0" + minsold; }
 if (seconds < 10) { seconds = "0" + seconds; }
 if (hrsold < 0) {
  $(".seckill_time").html("0");
  $(".seckill_minute").html("0");
  $(".seckill_second").html("0");
 } else {
  $(".seckill_time").html("").html(hrsold);
  $(".seckill_minute").html("").html(minsold);
  $(".seckill_second").html("").html(seconds);
 }
 });
});

希望本文所述对大家的c#程序设计有所帮助。