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SQL中Group分组获取Top N方法实现可首选row_number

程序员文章站 2023-12-10 23:48:46
有产品表,包含id,name,city,addtime四个字段,因报表需要按城市分组,统计每个城市的最新10个产品,便向该表中插入了100万数据,做了如下系列测试: 复制代...
有产品表,包含id,name,city,addtime四个字段,因报表需要按城市分组,统计每个城市的最新10个产品,便向该表中插入了100万数据,做了如下系列测试:
复制代码 代码如下:

create table [dbo].[products](
[id] [int] identity(1,1) not null,
[name] [nvarchar](50) null,
[addtime] [datetime] null,
[city] [nvarchar](10) null,
constraint [pk_products] primary key clustered
(
[id] asc
)with (pad_index = off, statistics_norecompute = off, ignore_dup_key = off, allow_row_locks = on, allow_page_locks = on) on [primary]
) on [primary]

1、采用row_number方法,执行5次,平均下来8秒左右,速度最快。
复制代码 代码如下:

select no, id,name,city
from (select no =row_number() over (partition by city order by addtime desc), * from products)t
where no< 11 order by city asc,addtime desc

2、采用cross apply方法,执行了3次,基本都在3分5秒以上,已经很慢了。
复制代码 代码如下:

select distinct b.id,b.name,b.city from products a
cross apply (select top 10 * from products where city = a.city order by addtime desc) b

3、采用count查询,只执行了两次,第一次执行到5分钟时,取消任务执行了;第二次执行到13分钟时,没有hold住又直接停止了,实在无法忍受。
复制代码 代码如下:

select id,name,city from products a
where ( select count(city) from products where a.city = city and addtime>a.addtime) < 10
order by city asc,addtime desc

4、采用游标方法,这个最后测试的,执行了5次,每次都是10秒完成,感觉还不错。
复制代码 代码如下:

declare @city nvarchar(10)
create table #top(id int,name nvarchar(50),city nvarchar(10),addtime datetime)
declare mycursor cursor for
select distinct city from products order by city asc
open mycursor
fetch next from mycursor into @city
while @@fetch_status =0
begin
insert into #top
select top 10 id,name,city,addtime from products where city = @city
fetch next from mycursor into @city
end
close mycursor
deallocate mycursor
select * from #top order by city asc,addtime desc
drop table #top

通过上述对比不难发现,在面临group获取top n场景时,可以首选row_number,游标cursor其次,另外两个就基本不考虑了,数据量大的时候根本没法使用。