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JS实现的字符串数组去重功能小结

程序员文章站 2023-12-04 22:46:40
本文实例讲述了js实现的字符串数组去重功能。分享给大家供大家参考,具体如下: 这里只考虑最简单字符串的数组去重,暂不考虑,对象,函数,nan等情况,这种用正则实现起来就吃...

本文实例讲述了js实现的字符串数组去重功能。分享给大家供大家参考,具体如下:

这里只考虑最简单字符串的数组去重,暂不考虑,对象,函数,nan等情况,这种用正则实现起来就吃力不讨好了。

非正则实现:es6实现

<script>
let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr){
 return [...new set(arr)]
}
console.log(unique(str_arr)) 
</script>

运行结果:

JS实现的字符串数组去重功能小结

es5实现

<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
  function unique(arr) {
    return arr.filter(function(ele, index, array) {
      return array.indexof(ele) === index
    })
  }
  console.log(unique(str_arr))
</script>

运行结果同上

es3实现

<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
  var obj = {},
    array = []
  for (var i = 0, len = arr.length; i < len; i++) {
    var key = arr[i] + typeof arr[i]
    if (!obj[key]) {
      obj[key] = true
      array.push(arr[i])
    }
  }
  return array
}
console.log(unique(str_arr))
</script>

运行结果同上

用正则实现

<script>
 var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
 function unique(arr) {
   return arr.sort().join(",,").
   replace(/(,|^)([^,]+)(,,\2)+(,|$)/g, "$1$2$4").
   replace(/,,+/g, ",").
   replace(/,$/, "").
   split(",")
 }
 console.log(unique(str_arr))
</script>

运行结果:

JS实现的字符串数组去重功能小结

感兴趣的朋友可以使用在线html/css/javascript代码运行工具http://tools.jb51.net/code/htmljsrun测试上述代码运行效果。

ps:这里再为大家提供几款相关工具供大家参考使用:

在线去除重复项工具:

在线文本去重复工具:

更多关于javascript相关内容还可查看本站专题:《javascript数组操作技巧总结》、《javascript字符与字符串操作技巧总结》、《javascript遍历算法与技巧总结》、《javascript查找算法技巧总结》、《javascript数学运算用法总结》、《javascript数据结构与算法技巧总结》及《javascript错误与调试技巧总结

希望本文所述对大家javascript程序设计有所帮助。