JS实现的字符串数组去重功能小结
程序员文章站
2023-12-04 22:46:40
本文实例讲述了js实现的字符串数组去重功能。分享给大家供大家参考,具体如下:
这里只考虑最简单字符串的数组去重,暂不考虑,对象,函数,nan等情况,这种用正则实现起来就吃...
本文实例讲述了js实现的字符串数组去重功能。分享给大家供大家参考,具体如下:
这里只考虑最简单字符串的数组去重,暂不考虑,对象,函数,nan等情况,这种用正则实现起来就吃力不讨好了。
非正则实现:es6实现
<script> let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr){ return [...new set(arr)] } console.log(unique(str_arr)) </script>
运行结果:
es5实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.filter(function(ele, index, array) { return array.indexof(ele) === index }) } console.log(unique(str_arr)) </script>
运行结果同上
es3实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { var obj = {}, array = [] for (var i = 0, len = arr.length; i < len; i++) { var key = arr[i] + typeof arr[i] if (!obj[key]) { obj[key] = true array.push(arr[i]) } } return array } console.log(unique(str_arr)) </script>
运行结果同上
用正则实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.sort().join(",,"). replace(/(,|^)([^,]+)(,,\2)+(,|$)/g, "$1$2$4"). replace(/,,+/g, ","). replace(/,$/, ""). split(",") } console.log(unique(str_arr)) </script>
运行结果:
感兴趣的朋友可以使用在线html/css/javascript代码运行工具:http://tools.jb51.net/code/htmljsrun测试上述代码运行效果。
ps:这里再为大家提供几款相关工具供大家参考使用:
在线去除重复项工具:
在线文本去重复工具:
更多关于javascript相关内容还可查看本站专题:《javascript数组操作技巧总结》、《javascript字符与字符串操作技巧总结》、《javascript遍历算法与技巧总结》、《javascript查找算法技巧总结》、《javascript数学运算用法总结》、《javascript数据结构与算法技巧总结》及《javascript错误与调试技巧总结》
希望本文所述对大家javascript程序设计有所帮助。