C#生成不重复随机字符串类
程序员文章站
2023-12-04 17:46:05
本文实例讲述了c#生成不重复随机字符串类。分享给大家供大家参考。具体如下:
这个c#类用于随机产生不重复的字符串,可以指定字符串范围,可以指定要产生字符串的长度...
本文实例讲述了c#生成不重复随机字符串类。分享给大家供大家参考。具体如下:
这个c#类用于随机产生不重复的字符串,可以指定字符串范围,可以指定要产生字符串的长度
using system; namespace dotnet.utilities { public class randomoperate { // 一:随机生成不重复数字字符串 private int rep = 0; public string generatecheckcodenum(int codecount) { string str = string.empty; long num2 = datetime.now.ticks + this.rep; this.rep++; random random = new random(((int)(((ulong)num2) & 0xffffffffl)) | ((int)(num2 >> this.rep))); for (int i = 0; i < codecount; i++) { int num = random.next(); str = str + ((char)(0x30 + ((ushort)(num % 10)))).tostring(); } return str; } //方法二:随机生成字符串(数字和字母混和) public string generatecheckcode(int codecount) { string str = string.empty; long num2 = datetime.now.ticks + this.rep; this.rep++; random random = new random(((int)(((ulong)num2) & 0xffffffffl)) | ((int)(num2 >> this.rep))); for (int i = 0; i < codecount; i++) { char ch; int num = random.next(); if ((num % 2) == 0) { ch = (char)(0x30 + ((ushort)(num % 10))); } else { ch = (char)(0x41 + ((ushort)(num % 0x1a))); } str = str + ch.tostring(); } return str; } #region /// <summary> /// 从字符串里随机得到,规定个数的字符串. /// </summary> /// <param name="allchar"></param> /// <param name="codecount"></param> /// <returns></returns> private string getrandomcode(string allchar, int codecount) { //string allchar = "1,2,3,4,5,6,7,8,9,a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z"; string[] allchararray = allchar.split(','); string randomcode = ""; int temp = -1; random rand = new random(); for (int i = 0; i < codecount; i++) { if (temp != -1) { rand = new random(temp * i * ((int)datetime.now.ticks)); } int t = rand.next(allchararray.length - 1); while (temp == t) { t = rand.next(allchararray.length - 1); } temp = t; randomcode += allchararray[t]; } return randomcode; } #endregion } }
希望本文所述对大家的c#程序设计有所帮助。
上一篇: C#使用round函数四舍五入的方法
下一篇: Android设置控件阴影的三种方法