linux shell实现获取用户输入指定范围的单个字符的两种方法

方法一：

echo `echo {a..z}``echo {a..z}` > /tmp/letterfile
while read -p "please input a letter: " letter
do
    ((`awk -v var="$letter" 'begin{print length(var)}'` == 1)) && grep -q $letter /tmp/tmpfile && break
done
rm -f /tmp/letterfile
echo "you input letter $letter "

[root@station1 ~]# cat a.sh

echo `echo {a..z}``echo {a..z}` > /tmp/letterfile
while read -p "please input a letter: " letter
do
((`awk -v var="$letter" 'begin{print length(var)}'` == 1)) && grep -q $letter /tmp/tmpfile && break
done
rm -f /tmp/letterfile
echo "you input letter $letter "

[root@station1 ~]# chmod +x a.sh
[root@station1 ~]# ./a.sh
please input a letter: 123
please input a letter: abc
please input a letter: 4
please input a letter: &
please input a letter: (
please input a letter: a
you input letter a
[root@station1 ~]#

最初使用expr length $letter 替代 wk -v var="$letter" 'begin{print length(var)}'的，但是，当输入*等特殊字符时，会报错。
如下：
[root@station1 ~]# cat data

while read -p "please input a letter: " letter
do
((`expr length $letter` == 1)) && expr $letter : [[:alnum:]] > /dev/null && break
done
echo "you input letter $letter "

[root@station1 ~]# bash data
please input a letter: 123
please input a letter: abc
please input a letter: a
you input letter a
[root@station1 ~]# bash data
please input a letter: *
expr: 语法错误
data: line 3: ((: == 1: syntax error: operand expected (error token is "== 1")
please input a letter:

来看方法二：

while read -p "please input a letter: " letter
do
[[ `echo $letter | awk '/^[[:alpha:]]$/{print "1"}'` -eq 1 ]] && break
done
echo "you input letter $letter "

如下：
[root@station1 ~]# cat b.sh

while read -p "please input a letter: " letter
do
[[ `echo $letter | awk '/^[[:alpha:]]$/{print "1"}'` -eq 1 ]] && break
done
echo "you input letter $letter "

[root@station1 ~]# chmod +x b.sh
[root@station1 ~]# ./b.sh
please input a letter: *
please input a letter: abc
please input a letter: 234
please input a letter: )
please input a letter: t
you input letter t
[root@station1 ~]#