Python实现删除Android工程中的冗余字符串
android提供了一套很方便的进行资源(语言)国际化机制,为了更好地支持多语言,很多工程的翻译往往会放到类似crowdin这样的平台上。资源是全了,但是还是会有一些问题。
哪些问题
以下使用一些语言进行举例。其中values为工程默认的资源。
1.某语言的资源和某语言限定区域的资源之间。如values-fr-rca存在于values-fr相同的字符串,这种表现最为严重。
2.某语言的资源和默认的资源之间。values-fr存在与values相同的字符串,可能原因是由于values-fr存在未翻译字符串导致
为什么要去重
洁癖,容不下半点冗余。
解决思路
1.如果values-fr-rca存在于values-fr相同的字符串,去除values-fr-rca中的重复字符串,保留values-fr。这样可以保证在values-fr-rca下也可以正确读取到资源。
2.如果values-fr存在与values相同的字符串。如去除values-fr中得重复字符串,保留values的条目。
py脚本
#!/usr/bin/env python
# coding=utf-8
from os import listdir,path, system
from sys import argv
try:
import xml.etree.celementtree as et
except importerror:
import xml.etree.elementtree as et
def genregionlangpair(filepath):
basiclanguage = none
if ('values' in filepath) :
hasregionlimit = ('r' == filepath[-3:-2])
if (hasregionlimit):
basiclanguage = filepath[0:-4]
if (not path.exists(basiclanguage)) :
return none
belongstoenglish = ("values-en" in basiclanguage)
if (belongstoenglish):
#compare with the res/values/strings.xml
return (path.dirname(basiclanguage) + '/values/strings.xml', filepath + "/strings.xml")
else:
return (basiclanguage + '/strings.xml', filepath + "/strings.xml")
return none
def genlangpair(filepath):
def shouldgenlanpair(filepath):
if (not 'values' in filepath ):
return false
if('dpi' in filepath):
return false
if ('dimes' in filepath):
return false
if ('large' in filepath):
return false
return true
if(shouldgenlanpair(filepath)):
basiclanguage = path.dirname(filepath) + '/values/strings.xml'
targetlanguage = filepath + '/strings.xml'
if (not path.exists(targetlanguage)):
return none
if (not path.samefile(basiclanguage,targetlanguage)) :
return (basiclanguage, targetlanguage)
return none
def gencomparelist(filepath):
comparelists = []
for file in listdir(filepath):
regionpair = genregionlangpair(filepath + '/' + file)
if (none != regionpair):
comparelists.append(regionpair)
languagepair = genlangpair(filepath + '/' + file)
if (none != languagepair) :
comparelists.append(languagepair)
return comparelists
def getxmlentries(filepath):
root = et.elementtree(file=filepath).getroot()
entries = {}
for child in root:
attrib = child.attrib
if (none != attrib) :
entries[attrib.get('name')] = child.text
print 'xmlentriescount',len(entries)
return entries
def rewriteregionfile(sourceentries, filepath):
if (not path.exists(filepath)):
return
et.register_namespace('xliff',"urn:oasis:names:tc:xliff:document:1.2")
tree = et.elementtree(file=filepath)
root = tree.getroot()
print root
totalcount = 0
removecount = 0
unremovecount = 0
print len(root)
toremovelist = []
for child in root:
totalcount = totalcount + 1
attrib = child.attrib
if (none == attrib):
continue
childname = attrib.get('name')
if (sourceentries.get(childname) == child.text):
removecount = removecount + 1
toremovelist.append(child)
else:
unremovecount = unremovecount + 1
print childname, sourceentries.get(childname), child.text
print filepath,totalcount, removecount,unremovecount
for aitem in toremovelist:
root.remove(aitem)
if (len(root) != 0 ):
tree.write(filepath, encoding="utf-8")
else:
command = 'rm -rf %s'%(path.dirname(filepath))
print command
system(command)
def main(projectdir):
lists = gencomparelist(projectdir + "/res/")
for item in lists:
print item
src = item[0]
dest = item[1]
rewriteregionfile(getxmlentries(src),dest)
if __name__ == "__main__":
if (len(argv) == 2) :
main(argv[1])
如何使用
python removerepeatedstrings.py your_android_project_root_dir
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