C#实现微信红包功能

本文实例为大家分享了c#仿微信红包功能的具体代码，供大家参考，具体内容如下

program.cs代码:

class program
  {
    static void main(string[] args)
    {
      //初始化要发起的红包基础数据
      double total = 100;
      int num = 50;
      double min = 0.01;
      string temp;
      bool flag = false;
      console.writeline(string.format("是否需要自定义红包金额和数量（默认{0}元/{1}人）y/n：", total, num));
      temp = console.readline();
      if (temp.trim().tolower().equals("y") || temp.trim().tolower().equals("yes"))
      {
        console.writeline("请输入你要发起的红包金额：");
        do
        {
          temp = console.readline();
          flag = double.tryparse(temp, out total);
          if (!flag)
          {
            console.writeline("金额必须为整数或小数，请重新输入：");
          }
        } while (!flag);
        console.writeline("请输入你要发起的红包个数：");
        do
        {
          temp = console.readline();
          flag = int.tryparse(temp, out num);
          if (!flag)
          {
            console.writeline("红包个数必须为整数，请重新输入：");
          }
        } while (!flag);
      }

      total -= min * num;
      if (total < 0)
      {
        console.writeline("抱歉，你的金额不足！");
        return;
      }

      //产生正态分布的随机红包金额，并计算相关的金额和数量保证数据的准确性
      double average = total / num;
      double variance = 1;
      random u1 = new random();
      random u2 = new random();
      double[] nums = new double[num];

      for (int i = 0; i < num; i++)
      {
        double? result = total;
        if (i < num - 1 && total > 0)
        {
          do
          {
            result = round((double)normal(u1.nextdouble(), u2.nextdouble(), average, variance), 2);
          } while (result == null || result < 0);
          if (total > result)
          {
            total = (double)round((total - (double)result), 2);
          }
          else
          {
            result = total;
            total = 0;
          }
        }
        else if (i == num - 1)
        {
          total = 0;
        }
        nums[i] = math.round(min + (double)result, 2); //浮点运算问题，这里需要四舍五入数据才正确

        console.writeline(string.format("第{0}个红包金额：{1}", i + 1, (min + result)));
        console.writeline("剩余金额：" + ((i != num - 1 && total == 0) ? min * (num - i - 1) : total + (min * (num - i - 1))));
      }
      console.writeline("最大金额：" + nums.max());
      console.writeline("最小金额：" + nums.min());
      console.writeline("总额：" + round(nums.sum(), 2));
      console.writeline("初始方差：" + variance);
      console.writeline("结果方差：" + variance(nums));
      console.writeline("按任意键退出！");

      console.readkey();
    }

    /// <summary>
    /// 产生符合正态分布的随机数
    /// </summary>
    /// <param name="u1">正态分布第一个随机数</param>
    /// <param name="u2">正态分布第二个随机数</param>
    /// <param name="averagevalue">正态期望(平均值)</param>
    /// <param name="variance">正态标准差(math.sqrt(方差))</param>
    /// <returns></returns>
    public static double? normal(double u1, double u2, double averagevalue, double variance)
    {
      double? result = null;
      try
      {
        result = averagevalue + math.sqrt(variance) * math.sqrt((-2) * math.log(u1)) * math.sin(2 * math.pi * u2);
      }
      catch (exception)
      {
        result = null;
      }

      return result;
    }

    /// <summary>
    /// 求一组数据的方差
    /// </summary>
    /// <param name="list">要求的数组</param>
    /// <returns></returns>
    public static double variance(double[] nums)
    {
      double average = nums.sum() / nums.length;
      double sum = 0;
      double variance = 0;
      foreach (double num in nums)
      {
        sum += math.pow((num - average), 2);
      }
      variance = sum / nums.length;

      return variance;
    }

    /// <summary>
    /// 截取小数指定小数位，且不四舍五入
    /// </summary>
    /// <param name="originnum">要截取的小数</param>
    /// <param name="lastnum">截取小数后位数</param>
    /// <returns></returns>
    public static double? round(double originnum, int lastnum)
    {
      double? result = null;
      int index = originnum.tostring().indexof('.');
      if (index != -1)
      {
        string temp = originnum.tostring();
        result = convert.todouble(temp.substring(0, index + 1) + temp.substring(index + 1, math.min(temp.length - index - 1, lastnum)));
      }
      if (result == 0)
      {
        result = null;
      }
      else if (index == -1)
      {
        result = originnum;
      }

      return result;
    }
  }

运行结果：

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。