php实现的日历程序
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2023-11-21 08:55:04
本文实例讲述了php实现的日历程序。分享给大家供大家参考。具体如下:
本文实例讲述了php实现的日历程序。分享给大家供大家参考。具体如下:
<?php ////判断$year和$month是否为空,如果为空就获取系统当前日期,否则用$_get获取 $year = empty($_get['year']) ? date("y"): $_get["year"]; $month = empty($_get['month']) ? date("m"): $_get["month"]; ////获取当前日期//// $today = date("ymj"); ////初始化日期数组//// $maxday = array("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20", "21","22","23","24","25","26","27","28","29","30","31"); $maxday_count = count($maxday); ////初始化星期数组//// $weekday = array("<font color='red'>sun</font>","mon","tue","wed","thu","fri","<font color='red'>sat</font>"); $weekday_count = count($weekday); $daynum = 0; $space = "<td> </td>"; $col = 0; ////打印表格头部//// ?> <form action="calendar.php" method="post" name="linked"> <table><tr><td colspan=3 align=center><a href="?year=<?php if($year-1 > 1900)echo $year-1;else echo $year;?>&month=<?php echo $month?>" onclick="javascript:document.linked.submit();" name="year"><<</a> <?php echo $year?> <a href="?year=<?php if($year+1 <2999) echo $year+1;else echo $year;?>&month=<?php echo $month?>" onclick="javascript:document.linked.submit();" name="year">>></a></td> <td> </td><td colspan=3 align=center><a href="?year=<?php echo $year?>&month=<?php if($month-1 >0) if($month-1 < 10)echo "0".($month-1); else echo $month-1; else echo $month;?>" onclick="javascript:document.linked.submit();" name="month"><<</a> <?php echo $month;?> <a href="?year=<?php echo $year?>&month=<?php if($month+1 <13) if($month+1 <10) echo "0".($month+1);else echo ($month+1); else echo $month;?>" onclick="javascript:document.linked.submit();" name="month">>></a></td></tr><tr><td colspan="8"></td></tr><tr> <?php ////打印星期列表//// while(list(,$weekvalue) = each($weekday)) echo "<td align=center> ".$weekvalue." </td>"; echo "</tr>"; ////打印日期列表//// //当月份为4,6,9,11的时候,从数组末尾删除一个值,也就是删除31这个值. if($month == 4 or $month == 6 or $month == 9 or $month == 11) { array_pop($maxday); $maxday_count--; } //先判断月份是否为2月,如果是的话再判断年份是否为闰年,如果是的话就从数组尾部移除2个值,否则就移除3个值. if($month == 2) { if($year % 4 == 0) { array_pop($maxday); array_pop($maxday); $maxday_count-=2; } else { array_pop($maxday); array_pop($maxday); array_pop($maxday); $maxday_count-=3; } } ////打印日期//// while($daynum < $maxday_count) { echo "<tr>"; while(list($colnum,$dayvalue) = each($maxday)) { //判断当前日期为一星期中的哪一天 $dayweek = date("w",strtotime($year."-".$month."-".$dayvalue)); //当当前日期处于第1个,也就是每个月的第1天的时候,在它前面补上相应的空格子 if($dayvalue == 1) for($i=0;$i<$dayweek;$i++) echo $space;//打印每个月空出的几个格子 $daynum++; //当打印日期的时候与当前日期字符串进行比较,如果相等就将字体标为红色. if($year.$month.$dayvalue == $today) { $u1 = "<b><u>"; $u2 = "</b></u>"; } else { $u1 = ""; $u2 = ""; } if($dayweek == 0 or $dayweek == 6) $color = "red"; else $color = "black"; echo "<td align=center><font color=".$color."> ".$u1.$dayvalue.$u2." </font></td>"; //用本周第几天这个值加1,如果是7的倍数就换行退出此轮循环(换行打印) if(($dayweek+1) % 7 == 0) { $col++; break; } } echo "</tr>"; } ?>
运行效果如下:
希望本文所述对大家的php程序设计有所帮助。
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