php中输出json对象的值(实现方法)
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2023-11-21 08:36:04
实例如下所示:
实例如下所示:
<!doctype html> <html> <body> <?php $json = '{"report":{"date":"2012-04-10","content":"abcdefght"}}'; $arr = (array) json_decode($json,true); echo '当前日期是:'. $arr['report']['date']; echo "<br/>"; echo '<pre>'; print_r($arr); echo '</pre>'; foreach($arr as $arrvalue) { foreach($arrvalue as $key=>$value) { echo "[$key] = $value <br />"; } } echo "<br/>"; ?> </body> </html>
<!doctype html> <html> <body> <?php $file_exists = file_exists("json.txt"); if( $file_exists ){ $myfile = fopen("json.txt", "r") or die(""); $content = fread($myfile,filesize("json.txt")); fclose($myfile); echo $content; echo "<br/>"; $arr=(array)json_decode($content,true); echo $arr['css']; echo "<br/>"; echo $arr['ajax']; } ?> </body> </html>
json.txt:
{ "ajax": "asynchronous javascript and xml", "css": "cascading style sheets" }
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