把文件复制N份的2个Shell脚本代码
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2023-11-18 16:01:16
测试时需要大量文件,所以写了脚本进行拷贝。有规律的文件名利于引用。
复制代码 代码如下:
#!/bin/sh
# file name : batchcp.sh...
测试时需要大量文件,所以写了脚本进行拷贝。有规律的文件名利于引用。
复制代码 代码如下:
#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# email: ablozhou@gmail.com
# date : 2008.3.31
echo "input your file name"
read filename
echo "how many times you want copy?"
read times
echo "your file name is ${filename}, you want to copy ${times} times."
base=`echo ${filename}|cut -d "." -f 1`
ext=`echo ${filename}|cut -d "." -f 2`
for(( i=0;i<${times};i++))
do
echo "copy ${base}.${ext} to ${base}$i.${ext} ..."
cp "${base}.${ext}" "${base}$i.${ext}"
done
另一个版本
复制代码 代码如下:
#!/bin/sh
# file name : batchcp.sh
# author: zhouhh
# email: ablozhou@gmail.com
# date : 2008.3.31
echo "input your file name"
read filename
echo "how many times you want copy?"
read times
echo "your file name is ${filename}, you want to copy ${times} times."
#find . and cut the left part of the file name using ##
ext=${filename##*.}
#find . and cut the right part of the file name using %
base=${filename%.*}
echo "base:$base"
echo "ext:$ext"
for(( i=0;i<${times};i++))
do
echo "copy ${base}.${ext} to ${base}$i.${ext} ..."
cp "${base}.${ext}" "${base}$i.${ext}"
done
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