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Python任意字符串转16, 32, 64进制的方法

程序员文章站 2023-11-17 10:32:19
python字符串转数字 import binascii s = 'test123456test' str_16 = binascii.b2a...

python字符串转数字

  import binascii

  s = 'test123456test'
  str_16 = binascii.b2a_hex(s.encode('utf-8')) # 字符串转16进制
  print(str_16)

  def basen(num, b):
    return ((num == 0) and "0") or \
        (basen(num // b, b).lstrip("0") + "0123456789abcdefghijklmnopqrstuvwxyz"[num % b])

  num_10 = int(str_16, 16) # 16进制转10进制
  print(num_10)

  str_32 = basen(num_10, 32) # 10进制转32进制
  print(str_32)

  num_10_2 = int(str_32, 32) # 32进制转10进制
  print(num_10_2)

  num_16 = hex(num_10) # 10进制转16进制数
  print(num_16)

  ss = str_16.decode('hex') # 16进制串转字符串
  print(ss)

执行结果

7465737431323334353674657374
2360797289681380981751517517542260
1q6asrk64p36d1l6pq6asrk
2360797289681380981751517517542260
0x7465737431323334353674657374l
test123456test

10进制转n进制

def base10ton(num,n):
  """change a to a base-n number.
  up to base-36 is supported without special notation."""
  num_rep={10:'a',
     11:'b',
     12:'c',
     13:'d',
     14:'e',
     15:'f',
     16:'g',
     17:'h',
     18:'i',
     19:'j',
     20:'k',
     21:'l',
     22:'m',
     23:'n',
     24:'o',
     25:'p',
     26:'q',
     27:'r',
     28:'s',
     29:'t',
     30:'u',
     31:'v',
     32:'w',
     33:'x',
     34:'y',
     35:'z'}
  new_num_string=''
  current=num
  while current!=0:
    remainder=current%n
    if 36>remainder>9:
      remainder_string=num_rep[remainder]
    elif remainder>=36:
      remainder_string='('+str(remainder)+')'
    else:
      remainder_string=str(remainder)
    new_num_string=remainder_string+new_num_string
    current=current/n
  return new_num_string

进阶版

  def basen(num, b):
    return ((num == 0) and "0") or \
       (basen(num // b, b).lstrip("0") + "0123456789abcdefghijklmnopqrstuvwxyz"[num % b])

64进制

  def encode_b64(n):
    table = '0123456789abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz-_'
    result = []
    temp = n
    if 0 == temp:
      result.append('0')
    else:
      while 0 < temp:
        result.append(table[temp % 64])
        temp /= 64
    return ''.join([x for x in reversed(result)])


  def decode_b64(str):
    table = {"0": 0, "1": 1, "2": 2, "3": 3, "4": 4, "5": 5,
         "6": 6, "7": 7, "8": 8, "9": 9,
         "a": 10, "b": 11, "c": 12, "d": 13, "e": 14, "f": 15, "g": 16,
         "h": 17, "i": 18, "j": 19, "k": 20, "l": 21, "m": 22, "n": 23,
         "o": 24, "p": 25, "q": 26, "r": 27, "s": 28, "t": 29, "u": 30,
         "v": 31, "w": 32, "x": 33, "y": 34, "z": 35,
         "a": 36, "b": 37, "c": 38, "d": 39, "e": 40, "f": 41, "g": 42,
         "h": 43, "i": 44, "j": 45, "k": 46, "l": 47, "m": 48, "n": 49,
         "o": 50, "p": 51, "q": 52, "r": 53, "s": 54, "t": 55, "u": 56,
         "v": 57, "w": 58, "x": 59, "y": 60, "z": 61,
         "-": 62, "_": 63}
    result = 0
    for i in xrange(len(str)):
      result *= 64
      result += table[str[i]]
    return result

java字符串转数字

biginteger integer = new biginteger(hexstring.tostring(), 16);
integer.tostring(32);
import java.math.biginteger;

public class main {
 public static void main(string[] argv) throws exception {
  biginteger bi = new biginteger("1023");
  bi = new biginteger("1111111111", 2); 
  string s = bi.tostring(2); 
  system.out.println(s);
  bi = new biginteger("1000", 8);

  system.out.println(s = bi.tostring(8));

  bi = new biginteger("1023"); 
  s = bi.tostring(); 
  system.out.println(s);

  bi = new biginteger("3ff", 16); 
  s = bi.tostring(16); 
  system.out.println(s);
 }
}

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