php 显示指定路径下的图片

function getalldirandfile($path)
{
if(is_file($path))
{
if(isimage($path))
{
$str="";
$str.='<table style="border:solid 1px blue;" width="95%">';
$str.="<tr>";
$path=iconv("gb2312","utf-8",$path);
$str.="<td width=80%>".$path."</td><td width=15%><img src=".$path." style='width:50px;height:50px;'></td>";
$str.="</tr>";
$str.="</table>";
echo $str;
}
}
else
{
$resource=opendir($path);
while ($file=readdir($resource))
{
if($file!="." && $file!="..")
{
getalldirandfile($path."/".$file);
}
}
}
}

function isimage($filepath)
{
$filetypearray=array("jpg","png","bmp","jpeg","gif","ico");
$filepath=strtolower($filepath);
$lastposition=strrpos($filepath,".");
$isimage=false;
if($lastposition>=0)
{
$filetype=substr($filepath,$lastposition+1,strlen($filepath)-$lastposition);
if(in_array($filetype,$filetypearray))
{
$isimage=true;
}
}
return $isimage;
}