Python3 实现爬取网站下所有URL方式
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2023-11-14 14:57:16
获取首页元素信息:
目标 test_url:http://www.xxx.com.cn/
首先检查元素,a 标签下是我们需要爬取得链接,通过获取链接路径,定位出我们需要的信息...
获取首页元素信息:
目标 test_url:http://www.xxx.com.cn/
首先检查元素,a 标签下是我们需要爬取得链接,通过获取链接路径,定位出我们需要的信息
soup = bs4(reaponse.text, "lxml") urls_li = soup.select("#mainmenu_top > div > div > ul > li")
首页的url链接获取:
完成首页的url链接获取,具体代码如下:
''' 遇到不懂的问题?python学习交流群:821460695满足你的需求,资料都已经上传群文件,可以自行下载! ''' def get_first_url(): list_href = [] reaponse = requests.get("http://www.xxx.com.cn", headers=headers) soup = bs4(reaponse.text, "lxml") urls_li = soup.select("#mainmenu_top > div > div > ul > li") for url_li in urls_li: urls = url_li.select("a") for url in urls: url_href = url.get("href") list_href.append(head_url+url_href) out_url = list(set(list_href)) for reg in out_url: print(reg)
遍历第一次返回的结果:
从第二步获取url的基础上,遍历请求每个页面,获取页面中的url链接,过滤掉不需要的信息
具体代码如下:
def get_next_url(urllist): url_list = [] for url in urllist: response = requests.get(url,headers=headers) soup = bs4(response.text,"lxml") urls = soup.find_all("a") if urls: for url2 in urls: url2_1 = url2.get("href") if url2_1: if url2_1[0] == "/": url2_1 = head_url + url2_1 url_list.append(url2_1) if url2_1[0:24] == "http://www.xxx.com.cn": url2_1 = url2_1 url_list.append(url2_1) else: pass else: pass else: pass else: pass url_list2 = set(url_list) for url_ in url_list2: res = requests.get(url_) if res.status_code ==200: print(url_) print(len(url_list2))
递归循环遍历:
递归实现爬取所有url,在get_next_url()函数中调用自身,代码如下:
get_next_url(url_list2)
全部代码如下:
import requests from bs4 import beautifulsoup as bs4 head_url = "http://www.xxx.com.cn" headers = { "user-agent": "mozilla/5.0 (windows nt 10.0; win64; x64) applewebkit/537.36 (khtml, like gecko) chrome/72.0.3626.121 safari/537.36" } def get_first_url(): list_href = [] reaponse = requests.get(head_url, headers=headers) soup = bs4(reaponse.text, "lxml") urls_li = soup.select("#mainmenu_top > div > div > ul > li") for url_li in urls_li: urls = url_li.select("a") for url in urls: url_href = url.get("href") list_href.append(head_url+url_href) out_url = list(set(list_href)) return out_url def get_next_url(urllist): url_list = [] for url in urllist: response = requests.get(url,headers=headers) soup = bs4(response.text,"lxml") urls = soup.find_all("a") if urls: for url2 in urls: url2_1 = url2.get("href") if url2_1: if url2_1[0] == "/": url2_1 = head_url + url2_1 url_list.append(url2_1) if url2_1[0:24] == "http://www.xxx.com.cn": url2_1 = url2_1 url_list.append(url2_1) else: pass else: pass else: pass else: pass url_list2 = set(url_list) for url_ in url_list2: res = requests.get(url_) if res.status_code ==200: print(url_) print(len(url_list2)) get_next_url(url_list2) if __name__ == "__main__": urllist = get_first_url() get_next_url(urllist)
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