矩阵快速幂 hdu1757
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2022-03-16 18:45:52
...
#include <iostream>
#include <memory>
typedef long long ll;
using namespace std;
struct matrix
{
int m[10][10];
};
matrix ans, base, m;
matrix multi(matrix a, matrix b,ll mod)
{
matrix tmp;
for (int i = 0; i < 10; ++i)
{
for (int j = 0; j < 10; ++j)
{
tmp.m[i][j] = 0;
for (int k = 0; k < 10; ++k)
tmp.m[i][j] = (tmp.m[i][j] + (a.m[i][k] * b.m[k][j])) % mod;
}
}
return tmp;
}
matrix fastm(matrix base, ll n,ll mod )
{
int i = 0, j = 0;
matrix ans;
memset(ans.m, 0, sizeof(ans.m));
for (i = 0; i < 10; i++)
ans.m[i][i] = 1;
while (n)
{
if (n & 1)
{
ans = multi(ans, base,mod);
}
base = multi(base, base,mod);
n >>= 1;
}
return ans;
}
int main()
{
ll k,mod, sum ; int i;
matrix m, ans;
while (scanf("%I64d%I64d", &k, &mod) == 2)
{
sum = 0ll;
memset(m.m, 0, sizeof(m.m));
for (i = 1; i < 10; i++)
m.m[i][i - 1] = 1;//m是系数方阵
for (i = 0; i < 10; i++)
scanf("%d", &m.m[0][i]);
if (k<10)
{
printf("%d\n",k);
continue;
}
k -= 9;
ans = fastm(m, k,mod);
for (i = 0; i < 10; i++)
sum += (ans.m[0][i] * (9 - i)) % mod;
printf("%d\n", sum%mod);
}
return 0;
}
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