获取MSSQL 表结构中字段的备注、主键等信息的sql

1、mssql2000

select
表名 = case when a.colorder=1 then d.name else '' end,
表说明 = case when a.colorder=1 then isnull(f.value,'') else '' end,
字段序号 = a.colorder,
字段名 = a.name,
标识 = case when columnproperty( a.id,a.name,'isidentity')=1 then '√'else '' end,
主键 = case when exists(select 1 from sysobjects where xtype='pk' and parent_obj=a.id and name in (
select name from sysindexes where indid in(
select indid from sysindexkeys where id = a.id and colid=a.colid))) then '√' else '' end,
类型 = b.name,
占用字节数 = a.length,
长度 = columnproperty(a.id,a.name,'precision'),
小数位数 = isnull(columnproperty(a.id,a.name,'scale'),0),
允许空 = case when a.isnullable=1 then '√'else '' end,
默认值 = isnull(e.text,''),
字段说明 = isnull(g.[value],'')
from
syscolumns a
left join
systypes b
on
a.xusertype=b.xusertype
inner join
sysobjects d
on
a.id=d.id and d.xtype='u' and d.name<>'dtproperties'
left join
syscomments e
on
a.cdefault=e.id
left join
sysproperties g
on
a.id=g.id and a.colid=g.smallid
left join
sysproperties f
on
d.id=f.id and f.smallid=0
where
d.name='fi_dept' --如果只查询指定表,加上此条件
order by

a.id,a.colorder

2、mssql2005

use test--数据库
go
--2005实现字段属性统计(2000里的系统表sysproperties描述表、字段不存在，2005里用sys.extended_properties视图替代)
select
[表名]=c.name,
[表说明]=isnull(f.[value],''),
[列名]=a.name,
[列序号]=a.column_id,
[标识]=case when is_identity=1 then '√' else '' end,
[主键]=case when exists(select 1 from sys.objects where parent_object_id=a.object_id and type=n'pk' and name in
(select name from sys.indexes where index_id in
(select indid from sysindexkeys where and colid=a.column_id)))
then '√' else '' end,
[类型]=b.name,
[字节数]=case when a.[max_length]=-1 and b.name!='xml' then 'max/2g'
when b.name='xml' then ' 2^31-1字节/2g'
else rtrim(a.[max_length]) end,
[长度]=columnproperty(a.object_id,a.name,'precision'),
[小数]=isnull(columnproperty(a.object_id,a.name,'scale'),0),
[是否為空]=case when a.is_nullable=1 then '√' else '' end,
[列说明]=isnull(e.[value],''),
[默认值]=isnull(d.text,'')
from
sys.columns a
left join
sys.types b on a.user_type_id=b.user_type_id
inner join
sys.objects c on a.object_id=c.object_id and c.type='u'
left join
syscomments d on a.default_object_id=d.id
left join
sys.extended_properties e on e.major_id=c.object_id and e.minor_id=a.column_id and e.class=1
left join
sys.extended_properties f on f.major_id=c.object_id and f.minor_id=0 and f.class=1
[/code]
结果：