mssql sqlserver with cte表达式(递归)找出最顶值的方法分享

摘要: 下文通过递归的方式找出最*部门的方法分享，如下所示: 实验环境:sql server 2008 r2

---

下文通过cte-with表达式实现递归，获取一个公司的*部门，如下所示 例:部门表

create table [maomao365.com]
(keyid int ,parentid int,
deptname nvarchar(30))

insert into [maomao365.com]
(keyid,parentid,deptname)
values
(1,0,'总经办'),
(2,0,'it中心'),
(10,1,'销售部'),
(11,1,'售后部'),
(111,11,'售后1'),
(1111,111,'售后1_1'),
(12,1,'市场部'),
(21,2,'运维部'),
(22,2,'开发部')

---例1:获取 售后部keyid=1111所在的*部门
;
with testa( [keyid], [parentid],deptname)
as
(
select keyid, parentid,deptname
from [maomao365.com]
where keyid = 1111
union all
select a.keyid, a.parentid,a.deptname
from [maomao365.com] a
inner join testa on a.[keyid] = testa.[parentid]  --递归
)

select * from testa where parentid=0;


go

truncate table [maomao365.com]
drop  table [maomao365.com]

 

转自:http://www.maomao365.com/?p=7829