欢迎您访问程序员文章站本站旨在为大家提供分享程序员计算机编程知识!
您现在的位置是: 首页  >  IT编程

Python实现比较两个列表(list)范围

程序员文章站 2023-02-17 16:51:22
有一道题: 比较两个列表范围,如果包含的话,返回TRUE,否则FALSE。 详细题目如下: Create a function, this function receiv...

有一道题: 比较两个列表范围,如果包含的话,返回TRUE,否则FALSE。 详细题目如下:

Create a function, this function receives two lists as parameters, each list indicates a scope of numbers, the function judges whether list2 is included in list1.

 Function signature:
    differ_scope(list1, list2)

 Parameters:
    list1, list2    - list1 and list2 are constructed with strings,
                      each string indicates a number or a scope of
                      numbers. The number or scope are randomly, can
                      be overlapped. All numbers are positive.

                        E.g.
                            ['23', '44-67', '12', '3', '20-90']
 Return Values:
    True            - if all scopes and numbers indicated by list2 are included in list1.
    False           - if any scope or number in list2 is out of the range in list1.
 Examples:
    case1    - list1 = ['23', '44-67', '12', '3', '20-90']
               list2 = ['22-34', '33', 45', '60-61']
               differ_scope(list1, list2) == True
    case2    - list1 = ['23', '44-67', '12', '3', '20-90']
               list2 = ['22-34', '33', 45', '60-61', '100']
               differ_scope(list1, list2) == False

贴上自己写的代码如下:(备注: python 2.7.6)

def differ_scope(list1, list2): 
  print "list1:" + str(list1) 
  print "list2:" + str(list2) 
  #设置临时存放列表 
  list1_not_ = [] #用于存放列表1正常的数字值,当然要用int()来转换 
  list1_yes_ = [] #用于存放列表1中范围值如 44-67 
  list1_final = [] #用于存放列表1中最终范围值 如:[1,2,3,4,5,6,7,8,9,10] 
  temp1    = [] 
   
  list2_not_ = []  #用于存放列表2正常的数字值,当然要用int()来转换 
  list2_yes_ = []  #用于存放列表2中范围值如 44-67 
  list2_final= []  #用于存放列表2中最终范围值 如:[1,2,3,4,5,6,7,8,9,10] 
  temp2   = [] 
 
  temp    = []  #用于存放列表1,与列表2比较后的列表,从而判断结果为True还是False. 
   
  #对列表1进行处理 
  for i in range(len(list1)): #用FOR循环对列表1进行遍历 
    tag = 0 
    if list1[i].find('-')>0:#对含范围的数字进行处理,放到list_yes_列表中  
      strlist = list1[i].split('-') 
    list1_yes_ = range(int(strlist[0]),int(strlist[1])+1)#让其生成一个范围列表 
    for each in list1_yes_:     #FOR循环遍历所有符合条件的. 
        [temp1.append(each)] 
    else:           #对列表1中正常的数字进行处理,放到list_not_列表中 
      list1_not_.append(int(list1[i]))#对列表1中进行处理,放到list_yes_    
  [temp1.append(i) for i in list1_not_ if not i in temp1]#去除重复项 
  list1_final = sorted(temp1) #比较后,排序,并放到list1_final列表中 
  print "list1_final value is:" + str(list1_final)#打印排序后最终list1_final列表 
 
   
  #对列表2进行处理 
  for i in range(len(list2)): 
    if list2[i].find('-')>0: 
      strlist = list2[i].split('-') 
    list2_yes_ = range(int(strlist[0]),int(strlist[1])+1) 
    for each in list2_yes_: 
        [temp2.append(each)] 
      print "Temp2:" + str(temp2) 
    else: 
      list2_not_.append(int(list2[i])) 
  [temp2.append(i) for i in list2_not_ if not i in temp2] 
  list2_final = sorted(temp2) 
  print "list2_final value is:" + str(list2_final) 
 
  #对两个列表进行比较,得出最终比较结果. 
  [temp.append(i) for i in list2_final if not i in list1_final]#比较两个列表差值. 
  print "In list2 but not in list1:%s" % (temp)#打印出列表1与列表2的差值 
  if len(temp)>=1 : 
    print "The result is: False" 
  else: 
    print "The result is: True" 
 
if __name__ == '__main__': 
  list1 = ['23', '44-67', '12', '3','90-100'] 
  list2 = ['22-34', '33', '45'] 
  differ_scope(list1,list2) 

总结:
1. 这道题关键是想法,如果整成坐标的方式来比较,会很麻烦。
2. 列表转成范围后,如果消除重复项,同样是里面的关键所在。
3. 其次是对列表遍历的操作,同样挺重要。