使用python 的matplotlib 画轨道实例
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2022-10-12 14:33:00
如下所示:
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.patches...
如下所示:
import numpy as np import matplotlib.pyplot as plt import matplotlib.patches as mpatches from scipy import stats fig = plt.figure() ax = fig.add_subplot(111, xlim=(0, 10), ylim=(-4, 4)) sx=0;sy=0;r=1.5 ; circle = mpatches.circle((sx,sy),r,ec='b',fc = 'b',alpha=0.6) ax.add_patch(circle) n = 5 alpha = np.linspace(-np.pi/2,np.pi/2,100) for i in range(1,n+1): a = (i+1)*2 b = (i+1) plt.plot(a*np.cos(alpha),b*np.sin(alpha)) if i <= 3: ax.text(a+1,0,'layer.%d'%(i-1),ha='center',va='center') rate = 3 jnum = 100 for i in range(jnum): data = stats.poisson.rvs(mu = rate, loc = 0 , size = 1) while data == 0: data = stats.poisson.rvs(mu = rate, loc = 0 , size = 1) data = data[0] r = np.random.random() beta = (np.random.random()-0.5)*np.pi print beta data += r a = (data+1)*2*np.cos(beta) b = (data+1)*np.sin(beta) ax.scatter(a,b, c='y',edgecolors = 'y') xx = [3.5 , 6.8,6.8] yy = [-1.8,0.9,3.1] pp = [1.00,0.85,0.75] rota = [-45,0,0] for i in range(3): plt.plot((1.5,xx[i]) , (0,yy[i]) , 'r') ax.scatter(xx[i],yy[i], c='y',edgecolors = 'b') ax.text(xx[i] , yy[i] , 'probability %lf'%pp[i] , ha = 'center' ) tx = np.linspace(0,10,10) ty = np.linspace(-4,-4,10) ax.set_xticks(tx) ax.set_xticklabels(('')) ax.set_yticks(ty) ax.set_yticklabels(('')) #plt.axis('off') plt.show()
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